Answer: answer is in the photo
Step-by-step explanation:
Step-by-step explanation:
The answer is 62/15.
I can't explain it bc I'm taking a test rn but still-
Answer:
<em><u>hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>helpful</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>you</u></em><em><u> </u></em>
Step-by-step explanation:
.....
Answer:
D. 2058.24 in³
Step-by-step explanation:
Let r,h be the radius and height of smaller can and R,H be the radius and height of larger can
Then, R=4r and H=4h
Volume of smaller can=32.16 in³
⇒ πr²h=32.16 in³
Volume of larger can= πR²H
= π(4r²)×4h
= 64πr²h
= 64×32.16 in³
= 2058.24 in³
Hence, correct option is:
D. 2058.24 in³
Hello :
q(r)=3<span>√(r²-16)
q exist : r² - 16 </span><span>≥ 0
r² </span><span>≥ 16
</span>√r² ≥ √16
but : √16 = 4 and √r² = <span>|r
|
</span>|r | ≥ 4
r ≤ 4 or r ≥ 4
the domain is : ] -∞, 4] ∪ [,4 , +
∞ [