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3 years ago

Use the table below. Find the total cost of 1 salad, 3 sandwiches, and 2 drinks. Use mental math.

Mathematics

1 answer:

zvonat [6]3 years ago

8 0

Answer:

$11.5

Step-by-step explanation:

Add all of them together

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Explain how to determine which numbers must be excluded from the domain of a rational expression. Please provide an example with

Katarina [22]

Answer:

When we are having a rational expression i.e. a expression of the type:

$\dfrac{f(x)}{g(x)}$

Where f(x) and g(x) are polynomial functions.

Now the domain of this rational expression is whole of the real numbers except the points where the function g(x) will be zero.

Hence we have to exclude the points where the given denominator quantity is zero.

Let us consider an example as:

Let R(x) denote the rational function as:

$R(x)=\dfrac{x^2}{(x-2)(x-3)}$

Now the domain of this rational function will be whole of the real line minus the points where the denominator is zero.

We know that (x-2)(x-3) is zero when x=2 or x=3.

Hence, the domain of R(x) is: R- {2,3}.

7 0

3 years ago

I need help with my Khan Acadmey work I don’t Understand any of it. Can someone help me Please

ohaa [14]

Answer:

x = 36

Step-by-step explanation:

144 + x = 36

*it's same side interior angles*

6 0

3 years ago

Evaluate the function rule for the given value.

lisabon 2012 [21]

I=<4 over theproduct 1/8 so thats your answer bye digger

4 0

3 years ago

Consider the differential equation <img src="https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20%20%5Cfrac%7Bdy%7D%7Bdx%7D%20%3D6%20y%5E%7

Nutka1998 [239]

As a Bernoulli equation:

$x^2\dfrac{\mathrm dy}{\mathrm dx}=6y^2+6xy\iff x^2y^{-2}\dfrac{\mathrm dy}{\mathrm dx}-6xy^{-1}=6$

Let $z=y^{-1}\implies\dfrac{\mathrm dz}{\mathrm dx}=-y^{-2}\dfrac{\mathrm dy}{\mathrm dx}$ . The ODE becomes

$-x^2\dfrac{\mathrm dz}{\mathrm dx}-6xz=6$
$x^6\dfrac{\mathrm dz}{\mathrm dx}+6x^5z=-6x^4$
$\dfrac{\mathrm d}{\mathrm dx}[x^6z]=-6x^4$
$x^6z=-6\displaystyle\int x^4\,\mathrm dx$
$x^6z=-\dfrac65x^5+C$
$z=-\dfrac6{5x}+\dfrac C{x^6}$
$y^{-1}=-\dfrac6{5x}+\dfrac C{x^6}$
$y=\dfrac1{\frac C{x^6}-\frac6{5x}}$
$y=\dfrac{5x^6}{C-6x^5}$

With $y(3)=6$ , we get

$6=\dfrac{5(3)^6}{C-6(3)^5}\implies C=\dfrac{4131}2$

so the solution is

$y=\dfrac{5x^6}{\frac{4131}2-6x^5}=\dfrac{10x^6}{4131-12x^5}$

which is valid as long as the denominator is not zero, which is the case for all $x\neq\sqrt[5]{\dfrac{4131}{12}}$ .

8 0

3 years ago

GUYS PLEASE SOMEBODY ANSWER THIS AS QUICK AS POSSIBLE I WILL GIVE YOU 50 POINTS

sergiy2304 [10]

Answer:

part A: 30,000 is more

Step-by-step explanation:

3 0

2 years ago