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3 years ago

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Suppose that a particular artillery piece has a range r = 9010 yards . find its range in miles. use the facts that 1mile=5280ft

and 3ft=1yard. express your answer in miles to three significant figures.

2 answers:

kipiarov [429]3 years ago

8 0

The given range is r = 9010 yards.

Note that
1 mile = 5280 ft
3 ft = 1 yard

Therefore the given range is
$r = (9010 \, yd)*(3 \, \frac{ft}{yd} )*( \frac{1}{5280} \, \frac{mi}{ft}) =5.1193 \, mi$

Answer: r = 5.119 miles (to 3 sig. figs)

Ivenika [448]3 years ago

3 0

Answer:The given range is r = 9010 yards.

Note that

1 mile = 5280 ft

3 ft = 1 yard

Therefore the given range is

r = (9010 \, yd)*(3 \, \frac{ft}{yd} )*( \frac{1}{5280} \, \frac{mi}{ft}) =5.1193 \, mi

Answer: r = 5.119 miles (to 3 sig. figs)

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