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mart [117]
3 years ago
10

4x+7=64 i need the answer

Mathematics
2 answers:
irina [24]3 years ago
7 0

Answer:

jniancun

Step-by-step explanation:

bhuybhubujb

dvvwdvwde

dvdv

Degger [83]3 years ago
6 0
X= 57/4 your welcomeeee
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Maria mows 2/3 of a lawn in 1/5 hour. How Many similar-sized lawns can she mow in 1 hour?
sp2606 [1]

Answer:

10/3 lawn

Step-by-step explanation:

2/3 of a lawn in 1/5 hour

-> 1 hour cab mow = 2/3(lawn) ÷ 1/5(hour)* 1(hour)

= 10/3 = 3,666666667 lawns

7 0
3 years ago
Read 2 more answers
Does anyone know how to solve this?
Bezzdna [24]

Use this version of the Law of Cosines to find side b:

b^2 = a^2 + c^2 − 2ac cos(B)

We want side b.

b^2 = (41)^2 + (20)^2 - 2(41)(20)cos(36°)

After finding b, you can use the Law of Sines to find angles A and C or use other forms of the Law of Cosines to find angles A and C.

Try it....

6 0
3 years ago
What is a time in the past that you celebrated something good that happened? its for my english class, and i dont know what do w
lapo4ka [179]

Answer:

Easter, Christmas, birthdays, and New Year

Step-by-step explanation:

For me, I would choose Easter because before easter we always go to a church and stay there whole night. After 3-4 a.m, we go home and take a nap. But the most fun activity that we do during Easter is playing a game where we pick the best eggs and beat with each other. Later, our parents hide eggs and a couple of toys in the park and me and my siblings begin finding them.

3 0
3 years ago
How do i do 3 part a ?
WINSTONCH [101]


In general the binomial expansion is


(a+b)^n = {n \choose 0} a^0 b^n + {n \choose 1} a^1 b^{n-1} + {n \choose 2} a^2 b^{n-2} + ... + {n \choose n} a^n b^0


So in our case, because we want ascending powers of x we'll write,


(-3x + 1)^{11} =  {11 \choose 0} (-3x)^0 1^{11} + {11 \choose 1} (-3x)^{1} 1^{10} + {11 \choose 2} (-3x)^{2} 1^9  + {11 \choose 3 } (-3x)^3 1^8 + ...


We need to calculate the binomial coefficients:


{11 \choose 0}  = 1


{11 \choose 1}  = 11


{11 \choose 2}  = \dfrac{11 \times 10}{2} = 55


{11 \choose 3}  = \dfrac{11 \times 10 \times 9}{3 \times 2} = 165


(-3x+1)^{11} =  1 (-3x)^0 1^{11}  + 11(-3x)^{1} 1^{10}  + 55 (-3x)^2 1^{9}  + 165 (-3x)^3 1^8 + ...


(1-3x)^{11} =  1 -33 x + 495 3x^2 - 4455 x^3+ ...



6 0
3 years ago
The steps used by Taylor to solve the equation 3(x - 2) = 6(2x + 1) + 6 are shown below:
alexandr1967 [171]
Both A and C are used within this problem. Distributing happens in the first and second step. Also, Inverse operations are used in nearly every step that is solving. 
6 0
3 years ago
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