Answer:
m∠ABE = 27°
Step-by-step explanation:
* Lets look to the figure to solve the problem
- AC is a line
- Ray BF intersects the line AC at B
- Ray BF ⊥ line AC
∴ ∠ABF and ∠CBF are right angles
∴ m∠ABF = m∠CBF = 90°
- Rays BE and BD intersect the line AC at B
∵ m∠ABE = m∠DBE ⇒ have same symbol on the figure
∴ BE is the bisector of angle ABD
∵ m∠EBF = 117°
∵ m∠EBF = m∠ABE + m∠ABF
∵ m∠ABF = 90°
∴ 117° = m∠ABE + 90°
- Subtract 90 from both sides
∴ m∠ABE = 27°
You know that it's a bot when it says "explanation in file".
They forgot to put a question, there's nothing to answer...
Answer:
i think its the last option.
Step-by-step explanation:
its not the first one because they it can be proved using AAS (but that option isnt available)
You can't prove it with SSS or ASA without more info
AAA doesn't exist
theirfore it must be the last option.
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