B.66 I am positively absolutely sure. Hope this helps!
Answer:
For this type of question you might want to give a domain in a set statement
ie.24 is less than 2(13,14,15,...)
<em><u>Or</u></em>
<em>If</em><em> </em><em>my</em><em> </em><em>fi</em><em>rst</em><em> </em><em>answer</em><em> </em><em>was</em><em> </em><em>a</em><em> </em><em>deviation</em><em> </em><em>then</em><em> </em><em> you</em><em> </em><em>were</em><em> </em><em>proba</em><em>bly</em><em> </em><em>being</em><em> </em><em>ask</em><em>ed</em><em> to</em><em> </em><em>subt</em><em>ract</em><em> </em><em>2</em><em>4</em><em> </em><em>fro</em><em>m</em><em> </em><em>2</em><em>t</em><em>i</em><em>m</em><em>e</em><em>s</em><em> </em><em>a</em><em> </em><em>giv</em><em>en</em><em> </em><em>num</em><em>ber</em><em> </em><em>being</em><em> </em><em>repres</em><em>e</em><em>nted</em><em> </em><em> </em><em>by</em><em> </em><em>the</em><em> </em><em>varia</em><em>ble</em><em> </em><em>x</em>
Answer:
C 111
Step-by-step explanation:
Answer:
They bought 5
Step-by-step explanation:
65x+40y=765
65(5)+40(11)=765
Part A;
There are many system of inequalities that can be created such that only contain points C and F in the overlapping shaded regions.
Any system of inequalities which is satisfied by (2, 2) and (3, 4) but is not stisfied by <span>(-3, -4), (-4, 3), (1, -2) and (5, -4) can serve.
An example of such system of equation is
x > 0
y > 0
The system of equation above represent all the points in the first quadrant of the coordinate system.
The area above the x-axis and to the right of the y-axis is shaded.
Part 2:
It can be verified that points C and F are solutions to the system of inequalities above by substituting the coordinates of points C and F into the system of equations and see whether they are true.
Substituting C(2, 2) into the system we have:
2 > 0
2 > 0
as can be seen the two inequalities above are true, hence point C is a solution to the set of inequalities.
Part C:
Given that </span><span>Natalie
can only attend a school in her designated zone and that Natalie's zone is
defined by y < −2x + 2.
To identify the schools that
Natalie is allowed to attend, we substitute the coordinates of the points A to F into the inequality defining Natalie's zone.
For point A(-3, -4): -4 < -2(-3) + 2; -4 < 6 + 2; -4 < 8 which is true
For point B(-4, 3): 3 < -2(-4) + 2; 3 < 8 + 2; 3 < 10 which is true
For point C(2, 2): 2 < -2(2) + 2; 2 < -4 + 2; 2 < -2 which is false
For point D(1, -2): -2 < -2(1) + 2; -2 < -2 + 2; -2 < 0 which is true
For point E(5, -4): -4 < -2(5) + 2; -4 < -10 + 2; -4 < -8 which is false
For point F(3, 4): 4 < -2(3) + 2; 4 < -6 + 2; 4 < -4 which is false
Therefore, the schools that Natalie is allowed to attend are the schools at point A, B and D.
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