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Whitepunk [10]
3 years ago
12

Find the measure of the missing angles

Mathematics
2 answers:
Ipatiy [6.2K]3 years ago
6 0
1- 38
2-90
3-38
hopefully i’m right i’m not 100% sure though :)
Serhud [2]3 years ago
3 0
Angle 1 is 52 angle 2 is 79 angle 3 is 38
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So for part a the answer with be 11/6
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At the supermarket you can fill your own honey bear container. A customer buys 12 oz of honey for $5.40. How much does honey cos
kondor19780726 [428]

Answer:

<u>The honey costs US$ 0.45 per ounce</u>

Step-by-step explanation:

1. Let's review the information given for solve the question:

Cost of the honey at the supermarket = US$ 5.40

Weight of the honey bought by the customer = 12 ounces

2. This is the formula to find out the cost per ounce:

Cost per ounce = Cost of the honey/Weight of the honey bought by the customer

Cost per ounce = 5.40/12

Cost per ounce = 0.45

<u>The honey costs US$ 0.45 per ounce</u>

3 0
3 years ago
Clarissas team collects m magazines for the recycling drive JoAnn team collects 3 times as many
WITCHER [35]

Answer: Clanssa’s team collects m magazines for the recycling drive. JoAnn’s team collects 3 times as many magazines as Clarissa’s team. JoAnn’s team collects a total of 654 magazines.​

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3 years ago
Suppose the number of radios in a household has a binomial distribution with parameters n=11 and p=40%. Find the probability of
Ivenika [448]

Answer:

Step-by-step explanation:

The formula for binomial distribution is expressed as

P(x=r) = nCr × q^(n-r) × p^r

From the information given,

n = 11

p = 40% = 40/100 = 0.4

q = 1 - 0.4 = 0.6

x represent the number of radios

a) P( x = 1) or P(x = 9)

P(x = 1) = 11C1 × 0.6^(11-1) × 0.4^1

P(x = 1) = 0.027

P(x = 9) = 11C9 × 0.6^(11-9) × 0.4^9

P(x = 9) = 0.0052

P( x = 1) or P(x = 9) = 0.027 + 0.0052 = 0.0322

b) P(x lesser than or equal to 7) = P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) + P(x = 4) + P(x = 5) + P(x = 6)

P(x = 0) = 11C0 × 0.6^(11-0) × 0.4^0 = 0.004

P(x = 1) = 0.027

P(x = 2) = 11C2 × 0.6^(11-2) × 0.4^2 = 0.089

P(x = 3) = 11C3 × 0.6^(11-3) × 0.4^3 = 0.177

P(x = 4) = 11C4 × 0.6^(11-4) × 0.4^4 = 0.24

P(x = 5) = 11C5 × 0.6^(11-5) × 0.4^5 = 0.22

P(x = 6) = 11C6 × 0.6^(11-6) × 0.4^6 = 0.15

P(x = 7) = 11C7 × 0.6^(11-7) × 0.4^7 = 0.15

P(x lesser than or equal to 7) = 0.004 + 0.027 + 0.089 + 0.177 + 0.24 + 0.22 + 0.15 + 0.07 = 0.977

c) P(x greater than or equal to 5) = 1 - P(x lesser than or equal to 4) = 1 - (0.004 + 0.027 + 0.089 + 0.177 + 0.24) = 1 - 0.537 = 0.463

d) P(x lesser than 9) = P(x lesser than or equal to 7) + P(x = 8)

P(x = 8) = 11C8 × 0.6^(11-8) × 0.4^8 = 0.02

P(x lesser than 9) = 0.977 + 0.02 = 0.997

e. P(x greater than 7) = 1 - P(x lesser than or equal to 7) = 1 - 0.977 = 0.023

5 0
3 years ago
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