Answer:
3
Step-by-step explanation:
Usually, when there is contamination the smallest amount can have huge ramifications in the data collected. In this scenario, if in a "clean" environment the trait is found in 2/10 frogs then anything above this number should be considered contaminated. This is because data above this ratio would be considered uncommon or rare and this unique occurrence can be most likely tied to the only new factor which would be the contamination. Therefore the minimum number of frogs with this trait in the sample would be 3.
140000 + 12000 = 152000
hope this helps
Answer:
Just remember this
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Step-by-step explanation:
According to my calculations, the LCM of the two denominators is 50. Therefore, since 50 goes into 50 a total of 1 times, you would multiply the top and bottom of the first fraction by 1. And since 1 goes into 50 a total of 50 times, you would multiply the top and bottom of the second fraction by 50. Now that the denominators are the same, you can simply compare the numerators to determine which fraction is greater. Since 21 is less than 2100, 21/50 is less than 2100/50. Therefore the 1st entry (21/50) is less than the 2nd entry (42).