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4 years ago

Find the area 12 6 5 14

Mathematics

1 answer:

oee [108]4 years ago

4 0

Answer:

Step-by-step explanation:

In this shape we have to use the formula: A= 1/2xbxh

So we use this formula. 1/2 X (5 X 14)= 35

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HELP NOW PLEASE

Stolb23 [73]

Did you get the awnser or no cause like well I don’t know

3 0

3 years ago

A survey was done that asked people to indicate whether they preferred running outdoors or running indoors. The results of the s

ser-zykov [4K]

Answer:

Option A. Divide 382 by 1027.

Step-by-step explanation:

A survey was done about the people who preferred running indoors and outdoors. Then a two way table was prepared.

Amir is making a relative frequency table.

As we know relative frequency table is prepared by the dividing number of frequency by the total number of students taken in the sample.

Now he will take the data from the given two way table.

People age 30 years and younger were 382 running outdoors and 105 running indoor.

So people having age 30 and below are 382 + 105 = 487

Similarly people Over 30 years old running outdoor and indoor = 299 + 241 = 541

Now Total number of people taken in the sample = 487 + 541 = 1027

So relative frequency for the people of age 30 and younger will be

382/1027 for outdoor and 105/1027 for indoor.

Therefore answer will be Option A. Divide by 382/1027.

3 0

3 years ago

One winter day, the temperature ranged from a high of 40 °F to a low of -5 °F. By how many degrees did the temperature change?

GalinKa [24]

Answer:

Step-by-step explanation:

the correct choice is C.

4 0

3 years ago

A tennis player hits a ball 3 feet above the ground with a velocity of 60 ft/sec. After how many seconds will the ball be at a h

9966 [12]

Answer:

The ball will be at a height of 3 feet above the ground after 3.729 seconds.

Step-by-step explanation:

Let suppose that the tennis player has hit the ball vertically, meaning that ball will experiment a free fall, that is, an uniform accelerated motion due to gravity. The time taken by the ball in terms of its initial velocity ( $v_{o}$ ), in feet per second, initial position ( $x_{o}$ ), in feet, final position ( $x$ ), in feet, and gravitational acceleration ( $g$ ), in feet per square second is described by this second order polynomial:

$x = x_{o} + v_{o}\cdot t + \frac{1}{2}\cdot g\cdot t^{2}$ (1)

If we know that $x_{o} = x = 3\,ft$ , $v_{o} = 60\,\frac{ft}{s}$ and $g = -32.174\,\frac{ft}{s^{2}}$ , then the time needed by the ball to be at a height of 3 feet again is:

$3\,ft = 3\,ft + \left(60\,\frac{ft}{s} \right)\cdot t + \frac{1}{2}\cdot \left(-32.174\,\frac{ft}{s^{2}} \right)\cdot t^{2}$

$-16.087\cdot t^{2}+60\cdot t = 0$ (2)

$t^{2} - 3.729\cdot t = 0$

$t \cdot (t -3.729) = 0$

The binomial contains the time when the ball will be at a height of 3 feet again. In other words, the ball will be at a height of 3 feet above the ground after 3.729 seconds.

3 0

3 years ago

HELP!!!! URGENT!!!

Kipish [7]

Step-by-step explanation:

Assume that all 93 cartons were 600mL.

Volume of milk = 93 * 0.6L = 55.8L

Difference between Actual and Total

= 79.8L - 55.8L = 24.0L

For every 600mL carton that becomes 1L,

the volume of milk will increase by 0.4L.

=> 24.0L / 0.4L = 60

Hence there were 60 1L cartons and 93 - 60 = 33 600mL cartons of milk.

3 0

3 years ago

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