Write an expression describing her earnings for working hours

For a moving object, the force acting on the object varies directly with the objects acceleration. When the force of 63 N acts o

Serjik [45]

Answer:

49N

Step-by-step explanation:

Step one

Given

When the force of 63 N acts on a certain object

the acceleration of the object is 9/ms^2

Firstly, we need to calculate the mass m

F=ma-------1

m= F/a

m= 63/9

m= 7kg

Step two:

Also, if the acceleration of the object becomes 7 m/s^2

then the force

Note: the mass remains the same= 7kg

F=ma

F=7*7

F= 49N

4 0

2 years ago

Line m has the equation y = 1/2x - 4

Mandarinka [93]

Answer:

As the slopes of both lines 'm' and 'n' are the same.

Therefore, we conclude that the equation x-2y=4 represents the equation of the line 'n' if lines m and n are parallel to each other.

Step-by-step explanation:

We know that the slope-intercept of line equation is

$y=mx+b$

Where m is the slope and b is the y-intercept

Given the equation of the line m

y = 1/2x - 4

comparing with the slope-intercept form of the line equation

y = mx + b

Therefore,

The slope of line 'm' will be = 1/2

We know that parallel lines have the 'same slopes, thus the slope of the line 'n' must be also the same i.e. 1/2

Checking the equation of the line 'n'

$x-2y=4$

solving for y to writing the equation in the slope-intercept form and determining the slope

$x-2y=4$

Add -x to both sides.

$x - 2y + (-x) = 4+(-x)$

$-2y = 4 - x$

Divide both sides by -2

$\frac{-2y}{-2}=\frac{-x+4}{-2}$

$y=\frac{1}{2}x-2$

comparing ith the slope-intercept form of the line equation

Thus, the slope of the line 'n' will be: 1/2

As the slopes of both lines 'm' and 'n' are the same.

Therefore, we conclude that the equation x-2y=4 represents the equation of the line 'n' if lines m and n are parallel to each other.

3 0

2 years ago

Didn’t learn this good

patriot [66]

.059, you move the decimal point two times to the left and the other way around when you want to convert into a percent

4 0

3 years ago

Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65

erma4kov [3.2K]

Answer:

Probability that the sample average is at most 3.00 = 0.98030

Probability that the sample average is between 2.65 and 3.00 = 0.4803

Step-by-step explanation:

We are given that the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65 and standard deviation 0.85.

Also, a random sample of 25 specimens is selected.

Let X bar = Sample average sediment density

The z score probability distribution for sample average is given by;

Z = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean = 2.65

$\sigma$ = standard deviation = 0.85

n = sample size = 25

(a) Probability that the sample average sediment density is at most 3.00 is given by = P( X bar <= 3.00)

P(X bar <= 3) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ <= $\frac{3-2.65}{\frac{0.85}{\sqrt{25} } }$ ) = P(Z <= 2.06) = 0.98030

(b) Probability that sample average sediment density is between 2.65 and 3.00 is given by = P(2.65 < X bar < 3.00) = P(X bar < 3) - P(X bar <= 2.65)

P(X bar < 3) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{3-2.65}{\frac{0.85}{\sqrt{25} } }$ ) = P(Z < 2.06) = 0.98030

P(X bar <= 2.65) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ <= $\frac{2.65-2.65}{\frac{0.85}{\sqrt{25} } }$ ) = P(Z <= 0) = 0.5

Therefore, P(2.65 < X bar < 3) = 0.98030 - 0.5 = 0.4803 .

8 0

3 years ago

The area in square feet of a rectangular field is x²-110x+3000. The width, in feet, is x−50. What is the length, in feet?

ioda

x-60 is the length. Multiply you get x2-110x=3000 this is a quadratic equation.

7 0

3 years ago