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horsena [70]
3 years ago
9

A lion paced up and down the ridge 10 times. The ridge is 5 ft. 3 in. long. How far did the lion travel? (12 in.=1 ft.)​

Mathematics
1 answer:
Setler79 [48]3 years ago
7 0

Answer:

105 ft.

Step-by-step explanation:

5 x 12 = 60

So 5 feet is 60 inches.

60 + 3 = 63

That makes the ridge 63 inches long.

When the lion went up the ridge, it traveled 63 inches.

When the lion went back down the ridge, it traveled another 63 inches, totaling 126 inches.

The lion did this 10 times.

126 x 10 = 1260

Divide 1260 by 12 to find the measurement in feet.

1260 ÷ 12 = 105

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Yep! an open dot is <

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Wayne bought an engagement ring for Tracy.
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It would be: 420 + (420 * 17.5%)
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4 0
3 years ago
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What is the surface area of the square pyramid represented by the net below?
4vir4ik [10]

Answer:

64 cm^2

Step-by-step explanation:

Square: 4*4 = 16

Triangles: 4((4*6)/2))

       = 4(24/2)

       = 4(12)

       = 48

Add the square and triangles together

       = 16 + 48

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6 0
3 years ago
What are the lower, middle, and upper quartiles of this data?
Grace [21]

Answer:

71, 71, 75, 85, 98, 98, 104, 111, 114, 122, 164

The middle quartile is 98.

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The upper quartile is 112.5

8 0
3 years ago
A post is supported by two wires (one on each side going in oppositedirections) creating an angle of 80° between the wires. The
Vladimir [108]

Using the Sine rule,

\frac{\sin A}{A}=\frac{\sin B}{B}=\frac{\sin C}{C}\begin{gathered} \text{Let A = 14m,} \\ Substituting the variables into the formula,Where the length of the wires are, AP = xm and BP = ym[tex]\begin{gathered} \frac{\sin80^0}{14}=\frac{\sin40^0}{x} \\ \text{Crossmultiply,} \\ x\times\sin 80^0=14\times\sin 40^0 \\ Divide\text{ both sides by }\sin 80^0 \\ x=\frac{14\sin40^0}{\sin80^0} \\ x=9.14m \end{gathered}

Hence, the length of wire AP (x) is 9.14m.

For wire BP (y)m,

Sum of angles in a triangle is 180 degrees,

A^0+P^0+B^0=180^0\begin{gathered} \text{Where A}^0=\text{ unknown,} \\ P^0=80^0\text{ and,} \\ B^0=40^0 \\ A^0+80^0+40^0=180^0 \\ A^0+120^0=180^0 \\ A^0=180^0-120^0 \\ A^0=60^0 \end{gathered}

Using the side rule to find the length of wire BP,

\begin{gathered} \frac{\sin 60^0}{y}=\frac{\sin 80^0}{14} \\ \text{Crossmultiply,} \\ y\times\sin 80^0=14\times\sin 60^0 \\ \text{Didive both sides by }\sin 80^0 \\ y=\frac{14\times\sin 60^0}{\sin 80^0} \\ y=12.31m \end{gathered}

Hence, the length of wire BP (y) is 12.31m

Therefore, the length of the wires are (9.14m and 12.31m).

4 0
1 year ago
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