Answer:
Explanation:
Parenchyma
1. They have thin cell wall.
2. Their cell wall is made up of cellulose.
3. They are unspecialized tissues.
4. The are found in soft part of the plant.
5. They undergo photosynthesis and can stored the food and also play important role in gaseous exchange.
6. There are spaces between the cells.
Collecchyma.
1. They are thick cell walls.
2. Their cell walls are made up of cellulose and lectin.
3. They are specialized tissues
4. They are found in plants leaves and petioles.
5 The do not undergo photosynthesis but act to give mechanical support to plants.
6. They have little intercellular spaces.
Parenchyma and collecchyma are both tissues found in plants..
Answer:
A. Oxygen
Explanation:
During cellular respiration the cell uses oxygen to break down sugar. When sugar breaks down it produces energy in which your body needs. Blood picks up oxygen and releses carbon dioxide into your lungs.
Hope this helps!!
Complete question:
In bird dogs, barking while trailing (B) is dominant to silent while trailing (b). A heterozygous barking trailer is bred to a silent female trailer. Various offspring resulted.
- What is the genotype of the male animal?
- What is the genotype of the female animal?
- How many different genotypes are possible among the offspring?
- What proportion of the offspring will be heterozygous barkers?
Answer and Explanation:
<u>Due to technical problems</u>, you will find the complete question, answer, and explanation in the attached files.
Answer:
Due to presence of water in these rocks.
Explanation:
The fossils of ferns, rushes, and primitive conifers can not be found in these rocks because these rocks are present under the sea millions of year ago. In this onondaga contains an abundant amount of coral fossils, crinoids, brachiopods, and trilobites due to their aquatic habitat. These organisms are present millions of years ago when this area comes under the sea so that's why the fossils of these organisms are present in these rocks.
Answer:
The answer is: B) Twice the true concentration
Explanation:
According to what was expressed in the problem, the experiment has to be done with 200 ul of solution, with 200 ul of DNS and finally with 400 ul of H2O. The expression in the problem says that 100 ul of solution is recovered and 100 ul of DNS are added, and 200 ul of H2O are added, but it is said that only half of the solution was added (100 ul of H2O), leading to a increase in glucose concentration.
