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Tamiku [17]
2 years ago
13

Help PLEASE!!! [URGENT]

Mathematics
1 answer:
babunello [35]2 years ago
6 0
The answer is c because its c
You might be interested in
Find the area of the figure
wolverine [178]
The area of the figure is 30 because u have to add an subtract the numbers on the side
4 0
2 years ago
If x=5, what is the perimeter of the rectangle whose length is 6x-4 and whose width is 3x+2? *
strojnjashka [21]

Answer:

86

Step-by-step explanation:

Given, x = 5

length of a rectangle = 6x-4 = 6 * 5 - 4 = 30-4 = 26

width of a rectangle = 3x + 2 = 3 * 5 + 2 = 15 + 2 = 17

Now , finding the perimeter of the rectangle :

Perimeter of a rectangle = 2 ( length + width )

                                          = 2 ( 26 + 17 )

                                          = 2 * 43

                                         = 86

Hope I helped!

Best regards !

- TheAnimeGirl

8 0
3 years ago
Use cylindrical coordinates. find the volume of the solid that is enclosed by the cone z = x2 + y2 and the sphere x2 + y2 + z2 =
sashaice [31]
Let R be the solid. Then the volume is

\displaystyle\iiint_R\mathrm dV=\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=\sqrt8}\int_{\zeta=r^2}^{\zeta=\sqrt{72-r^2}}r\,\mathrm d\zeta\,\mathrm dr\,\mathrm d\theta

which follows from the facts that

\begin{cases}x=r\cos\theta\\y=r\sin\theta\\z=\zeta\end{cases}\implies\mathrm dx\,\mathrm dy\,\mathrm dz=r\,\mathrm dr\,\mathrm d\theta\,\mathrm d\zeta
(by computing the Jacobian)

and

z=x^2+y^2=r^2\implies z+z^2=72\implies z=-9\text{ or }z=8
(we take the positive solution, since it's clear that R lies above the x-y plane)
r^2+z^2=72\implies z=\pm\sqrt{72-r^2}
(again, taking the positive root for the same reason)
z=r^2\implies 8=r^2\implies r=\sqrt8

\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=\sqrt8}\int_{\zeta=r^2}^{\zeta=\sqrt{72-r^2}}r\,\mathrm d\zeta\,\mathrm dr\,\mathrm d\theta
=\displaystyle2\pi\int_{r=0}^{r=\sqrt8}\int_{\zeta=r^2}^{\zeta=\sqrt{72-r^2}}r\,\mathrm d\zeta\,\mathrm dr
=\displaystyle2\pi\int_{r=0}^{r=\sqrt8}r(\sqrt{72-r^2}-r^2)\,\mathrm dr
=\displaystyle2\pi\int_{r=0}^{r=\sqrt8}(r\sqrt{72-r^2}-r^3)\,\mathrm dr
=\dfrac{32(27\sqrt2-35)\pi}3
7 0
3 years ago
Rearrange the formula a = v^2/ r for v
BabaBlast [244]
Isolate the v.

a = v^2/2

First multiply 2 to both sides

a(2) = v^2/2(2)

2a = v^2

Isolate the v, root both sides

√2a = √v^2
✓2a = v

✓2a = v should be your answer


Hope this helps
7 0
3 years ago
Please help do in 10min!!
Elena L [17]

Answer: Holding a tray


Step-by-step explanation:


3 0
3 years ago
Read 2 more answers
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