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Finger [1]
3 years ago
13

What are the zeros of f(x) = x(x-7)?

Mathematics
1 answer:
den301095 [7]3 years ago
3 0

Answer:

c. 0 and 7

Step-by-step explanation:

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ANSWER QUICK FOR BRAINIEST: When using scientific notation, a positive exponent means . . . the standard number is less than one
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10. Two plots of land, one square and other rectangle have same perimeter. If the rectangular field is of size 90 m by 70 m, whi
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I’ll give u brainliest!!<br> what is the area of shape 1, 2 and 3
nevsk [136]

Answer:

Shape 1: 25.915

Shape 2: 102.85

Shape 3: 142

Step-by-step explanation:

For shape 1, you have to divide 7.1 to get half the width of the triangle. You get 3.55 from that, and then finding the triangle itself you have to do 7.3*3.55 to get 25.915. For shape 2, you first do the harder parts (the triangles) and since there is two of them we don't need to half the width of each triangle. But first to get the width, we need to do 20-17.4=2.6. But since there are 2 triangles we need to divide that by 2 to get 1.3. Then you multiply that by 5.5 to get the final area of both triangles which is 7.15. Next you simply find the rectangle which is 17.4*5.5=95.7. You add the triangles area to get 102.85. Finally for shape 3 you simply do 7.1*20=142.

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In a recent awards​ ceremony, the age of the winner for best actor was 35 and the age of the winner for best actress was 54. For
Arada [10]

Answer:

The actress has the more extreme age because

Step-by-step explanation:

Given

Male Athletes:

x = 35

\=x = 42.1

SD = 6.6

Female Athletes

x = 54

\=x = 34.3

SD = 10.1

Required

Determine which athlete had more extreme age

To do this, we simply calculate the standard z score using

z = \frac{x - \=x}{SD}

For the actor:

z = \frac{35 - 42.1}{6.6}

z = \frac{-7.1}{6.6}

z = 1.0758

For the actress:

z = \frac{54 - 34.3}{10.1}

z = \frac{19.7}{10.1}

z = 1.950

Comparing both z values;

The actress has the more extreme age because

  • <em>It has a positive z value</em>
  • <em>Its z value is greater than that of the actor</em>

<em></em>

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