4, 5, and 7 are mutually coprime, so you can use the Chinese remainder theorem right away.
We construct a number
such that taking it mod 4, 5, and 7 leaves the desired remainders:

- Taken mod 4, the last two terms vanish and we have

so we multiply the first term by 3.
- Taken mod 5, the first and last terms vanish and we have

so we multiply the second term by 2.
- Taken mod 7, the first two terms vanish and we have

so we multiply the last term by 7.
Now,

By the CRT, the system of congruences has a general solution

or all integers
,
, the least (and positive) of which is 27.
Answer:
1/3x is less than or equal to 15
Step-by-step explanation:
assuming you want an equation?
1/3x is less than or equal to 15
its this sign < with line under (srry i don't have the symbol)
Answer: She would have 32 pieces of cand in her bag
Step-by-step explanation: 27+5=32
For
to be conservative, we need to have



Integrate the first PDE with respect to
:

Differentiate with respect to
:

Now differentiate
with respect to
:

So we have

so
is indeed conservative.