No, it is not.
4/7 ≈ 0.5714
3/5 = 0.6
Actually, 3/5 is greater than 4/7.
Another way you could do this is by multiplying 4/7 with 5/5 and by multiplying 3/5 with 7/7.
4/7 * 5/5 = 20/35
3/5 * 7/7 = 21/35
Have an awesome day! :)
To find the residual I would subtract the predicted value from the measured value so for x-value 1 the residual would be 2-2.6 = -0.6
