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3 years ago

ANSWER THE QUESTION FOR BRAINLIEST

Mathematics

2 answers:

AlladinOne [14]3 years ago

8 0

Answer:

Step-by-step explanation:

both functions are decreasing because the slope is negative :)

Nostrana [21]3 years ago

6 0

Answer: Function I equals 3 and Function II equals 1 and 5 over 7. Different y intercept , with a neutral slope, the functions slope are decreasing

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How many solutions 9x +2y =9 -3x + y=2

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3 years ago

The vertex of this parabola is at (-4, -1). When the y-value is 0, the x-value is 2. What is the coefficient of the squared term

satela [25.4K]

$\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
y=a(x-(-4))^2-1\implies y=a(x+4)^2-1
\\\\\\
\textit{now, we also know that }
\begin{cases}
y=0\\
x=2
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solve for "a"

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3 years ago

What is the slope of the graph of y=−8x+15 ?

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See the file attached (photo) above - That is the graph for (-(8*x))+15

Graph the line using the slope and y-intercept, or two points.

Slope: −8

y-intercept: (0,15)

x y

0 15

1 7

#CarryOnLearning

<h3>→XxKim02xX</h3>

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3 years ago

Expand (4x-3y)^4 using pascal's triangle ...?

jenyasd209 [6]

Using row 4:

coefficients are: 1, 4, 6, 4, 1 

a^4 + a^3b + a^2b^2 + ab^3 + b^4 

Now adding the coefficients: 

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Substitute a and b: 

a = 4x 

b = -3y 

1(4x)^4 + 4(4x)^3(-3y) + 6(4x)^2(-3y)^2 + 4(4x)(-3y)^3 + 1(-3y)^4 

Now simplify the above: 

256x^4 - 768x^3y + 864x^2y^2 - 432xy^3 + 81y^4

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4 years ago

Pls give me the full answer

nikdorinn [45]

All of the Questions are solved on the images shown below. These images are from Microsoft Whiteboard that I created.

<h2>I'm in sixth grade, and don't know how to answer 2 and 5. So I'm only going to answer questions 1, 3 and 4. </h2>

really sorry about that

1. Answer = 90m²

3. Answer = 50in²

4. Answer = 108cm²

yup, this is how weird i am

I took the screen shot of answer 3 before 1 lol!

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so sorry I couldn't help on all problems

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2 years ago