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3 years ago

How to simplify a product

Mathematics

2 answers:

Stella [2.4K]3 years ago

8 0

Answer:

simple marketing

Step-by-step explanation:

if you have simple marketing that is easily understandable then it will most likely get better sales

Lelu [443]3 years ago

8 0

Answer:

Step-by-step explanation:

example:

(2+x)(3x-4)

6x-8+3x*2-4x

2x-8+3x*2

3x+2x-8

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HELP ME PLEASE!!!

zaharov [31]

The correct answer to this question would be answer choice B.

To convert the decimal 0.56 to a fraction, first set it to a fraction over 100 which would be 56/100.

Then, because the question asks for the fraction to be in simplest form, look for the greatest common factor of the numerator and denominator or 56 and 100.

To find it, list out all of their factors:

56: 1, 2, 4, 7, 8 , 14, 28, 56

100: 1, 2, 4, 5, 10,20,25,50,100

Notice that out of all the factors listed, the greatest common factor listed is 4. Because of this, divide both the numerator and denominator by 4 to simplify your fraction to your answer: 14/25

5 0

3 years ago

Major league baseball’s fastest recorded pitch is 105 miles per hour.The distance between the pitchers mound and home plate is 6

vovikov84 [41]

Answer:

1.75 seconds to get to the batter

7 0

3 years ago

Find the value of the following expression (2^8 • 3^-5 • 6^0) write your answer in simplified form show all your steps Help Fast

vitfil [10]

${( {2}^{8} \times {3}^{ - 5} \times {6}^{0} })^{ - 2} \\ = \frac{1}{ {( {2}^{8} \times {3}^{ - 5} \times {6}^{0} })^{2} } \\ = \frac{1}{ {(256 \times \frac{1}{ {3}^{5} } \times 1 })^{2} } \\ = \frac{1}{ {(256 \times \frac{1}{243} \times 1 })^{2} } \\ = \frac{1}{ ({ \frac{256}{243} })^{2} } \\ = \frac{1}{ \frac{ {256}^{2} }{ {243}^{2} } } \\ = \frac{1}{ \frac{65536}{59049} } \\ = \frac{59049}{65536}$
The answer is 59049/65539
The value is 0.901

6 0

3 years ago

9.)Jeanne has 3 7/8 yards of fabric. She needs 1 1/4 yards to make a pair of

tatuchka [14]

She can make 3 shorts

4 0

2 years ago

Read 2 more answers

PLEASE HELP ASAP! I don’t recall how to do this!

MakcuM [25]

Answer:

Step-by-step explanation:

For a. we start by dividing both sides by 200:

$(1.05)^x=1.885$

In order to solve for x, we have to get it out from its position of an exponent. Do that by taking the natural log of both sides:

$ln(1.05)^x=ln(1.885)$

Applying the power rule for logs lets us now bring down the x in front of the ln:

x * ln(1.05) = ln(1.885)

Now we can divide both sides by ln(1.05) to solve for x:

$x=\frac{ln(1.885)}{ln(1.05)}$

Do this on your calculator to find that

x = 12.99294297

For b. we will first apply the rule for "undoing" the addition of logs by multipllying:

$ln(x*x^2)=5$

Simplifying gives you

$ln(x^3)=5$

Applying the power rule allows us to bring down the 3 in front of the ln:

3 * ln(x) = 5

Now we can divide both sides by 3 to get

$ln(x)=\frac{5}{3}$

Take the inverse ln by raising each side to e:

$e^{ln(x)}=e^{\frac{5}{3}}$

The "e" and the ln on the left undo each other, leaving you with just x; and raising e to the power or 5/3 gives you that

x = 5.29449005

For c. begin by dividing both sides by 20 to get:

$\frac{1}{2}=e^{.1x}$

"Undo" that e by taking the ln of both sides:

$ln(.5)=ln(e^{.1x})$

When the ln and the e undo each other on the right you're left with just .1x; on the left we have, from our calculators:

-.6931471806 = .1x

x = -6.931471806

Question d. is a bit more complicated than the others. Begin by turning the base of 4 into a base of 2 so they are "like" in a sense:

$(2^2)^x-6(2)^x=-8$

Now we will bring over the -8 by adding:

$(2^2)^x-6(2)^x+8=0$

We can turn this into a quadratic of sorts and factor it, but we have to use a u substitution. Let's let $u=2^x$

When we do that, we can rewrite the polynomial as

$u^2-6u+8=0$

This factors very nicely into u = 4 and u = 2

But don't forget the substitution that we made earlier to make this easy to factor. Now we have to put it back in:

$2^x=4,2^x=2$

For the first solution, we will change the base of 4 into a 2 again like we did in the beginning:

$2^2=2^x$

Now that the bases are the same, we can say that

x = 2

For the second solution, we will raise the 2 on the right to a power of 1 to get:

$2^x=2^1$

Now that the bases are the same, we can say that

x = 1

5 0

3 years ago