Write the equation of the line in slope intercept form.

vovikov84 [41]

Hey there!

The correct answer is no.

2 1/8 is not equal to -2 1/8.
This is because -2 1/8 contains a negative sign, meaning it is less.
If the number was larger with the negative sign, it'd be even smaller.

For example:

-2 1/8 > -3 1/8

Hope this helps you,
Have a wonderful day! :)

4 0

4 years ago

Read 2 more answers

Find all values of a such that (a-3)/sqrta=-sqrta

Mariana [72]

Answer:

From the Pythagorean theorem...

[ distance between (a, 7) and (2, 1) ]2 = [a - 2]2 + [7 - 1]2

And they tell us that the distance equals 3√5 , so

[ 3√5 ]2 = [a - 2]2 + [7 - 1]2

45 = [a - 2]2 + 36

9 = [a - 2]2

±√9 = a - 2

± 3 = a - 2

± 3 + 2 = a

a = 3 + 2 = 5 or a = -3 + 2 = -1

and

5 + -1 = 4

Step-by-step explanation:

hope dis helps

3 0

3 years ago

C=1/21.22.23+1/22.23.24+................+1/200.201.202 . = là dấu nhân

Aneli [31]

It looks like you have to find the value of the sum,

$C = \displaystyle \frac1{21\times22\times23} + \frac1{22\times23\times24} + \cdots + \frac1{200\times201\times202}$

so that the n-th term in the sum is

$\dfrac1{(21+(n-1))\times(21+n)\times(21+(n+1))} = \dfrac1{(n+20)(n+21)(n+22)}$

for 1 ≤ n ≤ 180.

We can then write the sum as

$\displaystyle C = \sum_{n=1}^{180} \frac1{(n+20)(n+21)(n+22)}$

Break up the summand into partial fractions:

$\dfrac1{(n+20)(n+21)(n+22)} = \dfrac a{n+20} + \dfrac b{n+21} + \dfrac c{n+22}$

Combine the fractions into one with a common denominator and set the numerators equal to one another:

$1 = a(n+21)(n+22) + b(n+20)(n+22) + c(n+20)(n+21)$

Expand the right side and collect terms with the same power of n :

$1 = a(n^2+43n+462)+b(n^2+42n+440) + c(n^2+41n + 420) \\\\ 1 = (a+b+c)n^2 + (43a+42b+41c)n + 462a+440b+420c$

Then

a + b + c = 0

43a + 42b + 41c = 0

462a + 440b + 420c = 1

==> a = 1/2, b = -1, c = 1/2

Now our sum is

$\displaystyle C = \sum_{n=1}^{180} \left(\frac1{2(n+20)}-\frac1{n+21}+\frac1{2(n+22)}\right)$

which is a telescoping sum. If we write out the first and last few terms, we have

C = 1/(2×21) - 1/22 + 1/(2×23)

… … + 1/(2×22) - 1/23 + 1/(2×24)

… … + 1/(2×23) - 1/24 + 1/(2×25)

… … + 1/(2×24) - 1/25 + 1/(2×26)

… … + … - … + …

… … + 1/(2×198) - 1/199 + 1/(2×200)

… … + 1/(2×199) - 1/200 + 1/(2×201)

… … + 1/(2×200) - 1/201 + 1/(2×202)

Notice the diagonal pattern of underlined and bolded terms that add up to zero (e.g. 1/(2×23) - 1/23 + 1/(2×23) = 1/23 - 1/23 = 0). So, like a telescope, the sum collapses down to a simple sum of just six terms,

C = 1/(2×21) - 1/22 + 1/(2×22) + 1/(2×201) - 1/201 + 1/(2×202)

which we simplify further to

C = 1/42 - 1/44 - 1/402 + 1/404

C = 1,115/1,042,118 ≈ 0.00106994

4 0

3 years ago

Solve the equation: x^3 + x^2 – 20x=0

Aneli [31]

Answer: x=0

Step-by-step explanation:

7 0

4 years ago

Read 2 more answers

There are five students wearing glasses. There are three more boys than girls wearing glasses. On your worksheet, solve the ques

Llana [10]

Answer:

Four boys and one girl.

Step-by-step explanation:

Total students wearing glasses = 5

Separate the students by x and x + 3. It is x + 3 for the boys because there are three more boys wearing glasses.

Girls = x

Boys = x + 3

Total = 5

Calculate:

x + x + 3 =5

2x + 3 =5

2x = 2

x = 1

Boys wearing glasses = (1) + 3 = 4

Girls wearing glasses = 1

3 0

4 years ago