Plz I need help!!!!!!!!!!!!!!!!!!

If the given values in a right triangle are cos A =

Vlad1618 [11]

See the picture attached to better understand the problem

we know that
in the right triangle ABC
cos A=AC/AB
cos A=1/3
so
1/3=AC/AB----->AB=3*AC-----> square----> AB²=9*AC²----> equation 1

applying the Pythagoras Theorem
BC²+AC²=AB²-----> 2²+AC²=AB²---> 4+AC²=AB²----> equation 2

substitute equation 1 in equation 2
4+AC²=9*AC²----> 8*AC²=4----> AC²=1/2----> AC=√2/2
so
AB²=9*AC²----> AB²=9*(√2/2)²----> AB=(3√2)/2

the answer is
the hypotenuse is (3√2)/2

5 0

3 years ago

A survey of 340 randomly chosen US adults found that 60% of the 150 men and 50% of the 190 women ran a five-kilometer race durin

Andrej [43]

Answer:

The p-value is less than the significance level, so we will reject the null hypothesis, and conclude that at 5% significance level, the proportion for women that ran 5 km is more than the proportion of male that ran the 5 km. Thus, women are more likely to run the 5 km race.

Step-by-step explanation:

We are given;

Number of males selected; n₁ = 150

Number of females selected; n₂ = 190

Proportion of the males; p₁ = 0.6

Proportion of females; p₂ = 0.5

Let's define the hypotheses;

Null hypothesis; H0: p₁ ≥ p₂

Alternative hypothesis; Ha: p₁ < p₂

Now, the z score formula for this is;

z = (p₁ - p₂)/√(p^(1 - p^))(1/n₁ + 1/n₂))

Where;

p^ = (p₁ + p₂)/2

p^ = (0.6 + 0.5)/2

p^ = 0.55

Thus;

z = (0.6 - 0.5)/√(0.55(1 - 0.55))((1/150) + (1/190))

z = 0.1/0.0543

z = 1.84

From online p-value from z-score calculator attached, using z = 1.84, significance level = 0.05, one tailed hypothesis, we have;

P-value = 0.033

The p-value is less than the significance level, so we will reject the null hypothesis, and conclude that at 5% significance level, the proportion for women that ran 5 km is more than the proportion of male that ran the 5 km. Thus, women are more likely to run the 5 km race.

Although if we check at 0.01 significance level, we will not have the same answer as the p-value will be greater.

3 0

3 years ago

Suppose that each semester at a particular community college Manuel has to pay $1478 in tuition and $121 in fees.

Kamila [148]

Answer:

Step-by-step explanation:

Let x be time, in semesters, remaining before Manuel graduates. We find that Manuel's expenses are:

$1478/semester in tuition, and

$121/semester in fees

1. x semesters remaining: fees

Remaining cost for fees, y, is the product of the fee times the number of semesters, x:

y =($121/semester)*x

y = ($121)*x

2. x semesters remaining: tuition

Remaining cost, y, is the product of the tuition (times the number of semesters, x.

y = ($1478/semester)*x + ($121/semester)*x

y = ($1599)*x

3. x semesters remaining: tuition and fees

Remaining cost, y, is the sum of the products of the tuition (times the number of semesters, and the fees (tix.

y = ($1478/semester)*x + ($121/semester)*x

y = ($1599)*x

5 0

1 year ago

Consider the polynomial function q(x) = 3x^4 – 5x^3 – 2x^2 + x – 18.

sergeinik [125]

Answer: As x —> positive infinity, q(x) —> positive infinity, and as x —> negative infinity, q(x) —> positive infinity

Step-by-step explanation:

Khan Academy! Hope this helps

3 0

3 years ago

Read 2 more answers

-pls answer all thanks!!! HAVE A BLESS DAY

blagie [28]

1. = 3
2.= 1
3.= 3/1= 3

5 0

2 years ago

Read 2 more answers