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3 years ago

I need help finding the rate of change can someone help me

Mathematics

1 answer:

Allisa [31]3 years ago

6 0

Answer:

rate of change is 4.

Step-by-step explanation:

rate of change is the slope, so, pick any two relations given to us in the table.

(-3, -14) and (-1, -6).

slope = y2 - y1/ x2 - x1

slope = -6 - (-14)/-1-(-3)

slope = 8/2 = 4.

the rate of change is 4.

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Darina [25.2K]

Answer:

A and B are correct

Step-by-step explanation:

It's asking what's true, so let me break this down for you.

If you look at the table, y has a row under the x row. Each of the boxes have numbers, and it's a so-called "pattern graph." A says, "The value of the function at x = 0 is y = 3." That means that the number 0 in the "x-row" has a 3 in the "y-row" (or below that number. That's all there is to it, and you just repeat this except different numbers, however... C and D aren't horizontal from each other so they are incorrect.

7 0

3 years ago

1 2 3 4 5

mylen [45]

Answer:

B) 8x10^(-8)

Hope it helps

7 0

2 years ago

Solve:<br> -8r - (-2r-3) = 13<br><br> (if you can give a step by step, that would be great!)

coldgirl [10]

Answer:

$r = - \frac{5}{3} = 1 \frac{2}{3} = - 1.6$

Step-by-step explanation:

$- 8r - ( - 2r - 3) = 13$

$- 8r + 2r + 3 = 13$

$- 6r + 3 = 13$

$- 6r = 13 - 3$

$- 6r = 10$

$\boxed{\green{r = - \frac{5}{3} = 1 \frac{2}{3} = - 1.6}}$

4 0

3 years ago

In a particular faculty 60% of students are men and 40% are women. In a random sample of 50 students what is the probability tha

zimovet [89]

Answer:

a) The expected value is given by:

$E(X) = np = 50*0.4 = 20$

and the variance is given by:

$Var(X) =np(1-p) = 50*0.4*(1-0.4) = 12$

b) $P(X>25)= 1-P(X\leq 25)$

And we can find this probability with the following Excel code:

=1-BINOM.DIST(25,50,0.4,TRUE)

And we got:

$P(X>25)= 1-P(X\leq 25)=0.0573$

c) 1) Random sample (assumed)

2) np= 50*0.4= 20 >10

n(1-p) =50*0.6= 30>10

3) Independence (assumed)

Since the 3 conditions are satisfied we can use the normal approximation:

$X \sim N(\mu = 20 , \sigma= 3.464)$

d) $P(X>25) = 1-P(Z< \frac{25-20}{3.464}) = 1-P(z$

e) $P(X>25)= P(X>25.5) = 1-P(X \leq 25.5)$

$P(X>25)= P(X>25.5) = 1-P(X \leq 25.5)= 1-P(Z$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=50, p=0.4)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Part a

The expected value is given by:

$E(X) = np = 50*0.4 = 20$

and the variance is given by:

$Var(X) =np(1-p) = 50*0.4*(1-0.4) = 12$

Part b

For this case we want to find this probability:

$P(X>25)= 1-P(X\leq 25)$

And we can find this probability with the following Excel code:

=1-BINOM.DIST(25,50,0.4,TRUE)

And we got:

$P(X>25)= 1-P(X\leq 25)=0.0573$

Part c

1) Random sample (assumed)

2) np= 50*0.4= 20 >10

n(1-p) =50*0.6= 30>10

3) Independence (assumed)

Since the 3 conditions are satisfied we can use the normal approximation:

$X \sim N(\mu = 20 , \sigma= 3.464)$

Part d

We want this probability:

$P(X>25) = 1-P(Z< \frac{25-20}{3.464}) = 1-P(z$

Part e

For this case we use the continuity correction and we have this:

$P(X>25)= P(X>25.5) = 1-P(X \leq 25.5)$

$P(X>25)= P(X>25.5) = 1-P(X \leq 25.5)= 1-P(Z$

4 0

3 years ago

What is the distance from point (– 1, 3) to the line 3x – 4y = 10?

natta225 [31]

Answer:

5 units

Step-by-step explanation:

The distance from a point (m, n ) to the line Ax + By + C = 0 is given by

d = $\frac{|Am+Bn+C|}{\sqrt{A^2+B^2} }$

For the point (- 1, 3 ) , with m = - 1 and n = 3

3x - 4y = 10 ( subtract 10 from both sides )

3x - 4y - 10 = 0

with A = 3 , B = - 4 , C = - 10

d = $\frac{|3(-1)+(-4)3-10|}{\sqrt{3^2+(-4)^2} }$

= $\frac{|-3-12-10|}{9+16}$

= $\frac{|-25|}{\sqrt{25} }$

= $\frac{25}{5}$

= 5

5 0

2 years ago