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ahrayia [7]
3 years ago
12

What is the solution to this inequality?

Mathematics
1 answer:
AlladinOne [14]3 years ago
7 0

Answer:

D

Step-by-step explanation:

The answer is D, because when you divide x by a negative the sign changes

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Use the Distributive Property on 45x-6
Alexandra [31]

Answer:

<h3>180</h3>

Step-by-step explanation:

<h3>45 × -6 = 45 × [10+(-6)]</h3><h3>45 × (10-6)</h3><h3>45 × 4</h3><h3>180</h3>
5 0
3 years ago
PLs help me on this..........
Serggg [28]

Answer:

247277 people

Step-by-step explanation:

6% of 243,000 = 14,580

243,000 + 14,580 = 257,580

4% of 257,580 = 10,303.2

Estimating 10,303.2 to 10,303

257,580 - 10,303 = 247277

3 0
3 years ago
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All of the following expressions have a value of 3 except _____. A -3(4 - 5) B |-2| + 1(3 - 2) C -8 ÷ -4 + 1 D 6 - 5 · 3
irakobra [83]
Answer choice D, A,B, and C both equal 3.
5 0
3 years ago
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Simplify <br> 1+sinx/cosx+cosx/1+sinx
Dmitry [639]
\frac{1 + sin(x)}{cos(x)} + \frac{cos(x)}{1 + sin(x)}
\frac{[1 + sin(x)][1 +sin(x)]}{cos(x)[1 + sin(x)]} + \frac{cos(x)[cos(x)]}{cos(x)[1 + sin(x)]}
\frac{1 + 2sin(x) + sin^{2}(x)}{cos(x)[1 + sin(x)]} + \frac{cos^{2}(x)}{cos(x)[1 + sin(x)]}
\frac{1 + 2sin(x) + sin^{2}(x) + cos^{2}(x)}{cos(x)[1 + sin(x)]}
\frac{1 + 2sin(x) + 1}{cos(x)[1 + sin(x)]}
\frac{1 + 1 + 2sin(x)}{cos(x)[1 + sin(x)]}
\frac{2 + 2sin(x)}{cos(x)[1 + sin(x)]}
\frac{2[1 + sin(x)]}{cos(x)[1 + sin(x)]}
\frac{2}{cos(x)}
2sec(x)
6 0
3 years ago
Which expression is equivalent to (-1.3x-4.5) - (-2.1x+3.6)?
timurjin [86]

Equivalent expressions are expressions with the same value.

The equivalent expression of (-1.3x - 4.5)- (-2.1x + 3.6) is 0.8x -8.1

Given that:

(-1.3x - 4.5)- (-2.1x + 3.6)

Open brackets

(-1.3x - 4.5)- (-2.1x + 3.6) = -1.3x - 4.5+ 2.1x - 3.6

Collect like terms

(-1.3x - 4.5)- (-2.1x + 3.6) = -1.3x + 2.1x - 4.5 - 3.6

(-1.3x - 4.5)- (-2.1x + 3.6) = 0.8x -8.1

Hence, the equivalent of (-1.3x - 4.5)- (-2.1x + 3.6) is 0.8x -8.1

Read more about equivalent expressions at:

brainly.com/question/18257981

6 0
3 years ago
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