How do you solve simple linear equations
2 answers:
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Answer:
35 <5m
35/5 < 5m/5
7 < m
m = 8,9,10,11,12,.......
a + 6 9
a + 6 - 6 9 -6
a 3
a = 3,4,5,6,7,......
8-g > 5
8 -g +g > 5 +g
8 > 5 +g
8 -5 > 5 -5 +g
3 > g
g =4,5,6,7,8.......
Step-by-step explanation:
Question:
The numerator and denominator of a fraction are in the ratio of 3 to 5. If the numerator and denominator are both decreased by 2, the fraction is now equal to .
If n = the numerator and d = the denominator, which of the following systems of equations could be used to solve the problem?
5n = 3d and n - 2 = 2d - 4
5n = 3d and 2n - 4 = d - 2
3n = 5d and 2n - 4 = d - 2
Answer:
5n = 3d and 2n – 4 = d – 2
Solution:
Let n be the numerator of the fraction and d be the denominator of the fraction.
Given the numerator and denominator of a fraction are in the ratio of 3 to 5.
This can be written as n : d = 3 : 5.
⇒ – – – – (1)
Do cross multiplication, we get
⇒ 5n = 3d
When the numerator and denominator are decreased by 2, the fraction is equal to .
⇒
Do cross multiplication, we get
⇒ 2(n –2)=1(d – 2)
⇒ 2n – 4 = d – 2
Hence, 5n = 3d and 2n – 4 = d – 2 can be used to solve the problem.