If the company provides 1 1/4 vacation days to its employees every month,how many vacation days does an employee get every year?

1 answer:

5 0

We know there are 12 months in a year so we would multiply 1 1/4 by 12. We can write 1 1/4 as 1.25 (to make it easier to multiply). 12x1.25=15
Your answer is 15 vacation days in one year

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What is the answer to this

____ [38]

Answer:

Step-by-step explanation:

Add up all the numbers:

3,2,2,2,1,1,1,4,2,1

Then you get 19.

Or you can say it as

3^2 + 2^4 + 1^4 + 4

7 0

3 years ago

Express f(x) = |x-2| +|x+2| in the non-modulus form. Hence, sketch the graph of f.

alexgriva [62]

Recall that

$|x|=\begin{cases}x&\text{if }x\ge0\\-x&\text{if }x$

There are three cases to consider:

(1) When $x+2$ , we have $|x+2|=-(x+2)$ and $|x-2|=-(x-2)$ , so

$|x-2|+|x+2|=-(x-2)-(x+2)=-2x-4$

(2) When $x+2\ge0$ and $x-2$ , we get $|x+2|=x+2$ and $|x-2|=-(x-2)$ , so

$|x-2|+|x+2|=-(x-2)+(x+2)=4$

(3) When $x-2\ge0$ , we have $|x+2|=x+2$ and $|x-2|=x-2$ , so

$|x-2|+|x+2|=(x-2)+(x+2)=2x$

So

$|x-2|+|x+2|=\begin{cases}-2x-4&\text{if }x$

4 0

3 years ago

Before every flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the ai

ollegr [7]

Answer:

The probability that the aircraft is overload = 0.9999

Yes , The pilot has to be take strict action .

Step-by-step explanation:

P.S - The exact question is -

Given - Before every flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the aircraft. The aircraft can carry 37 passengers, and a flight has fuel and baggage that allows for a total passenger load of 6,216 lb. The pilot sees that the plane is full and all passengers are men. The aircraft will be overloaded if the mean weight of the passengers is greater than 6216/37 = 168 lb. Assume that weight of men are normally distributed with a mean of 182.7 lb and a standard deviation of 39.6.

To find - What is the probability that the aircraft is overloaded ?

Should the pilot take any action to correct for an overloaded aircraft ?

Proof -

Given that,

Mean, μ = 182.7

Standard Deviation, σ = 39.6

Now,

Let X be the Weight of the men

Now,

Probability that the aircraft is loaded be

P(X > 168 ) = P( $\frac{x - \mu}{\sigma} > \frac{168 - \mu}{\sigma}$ )