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3 years ago

Divide -1/6 divided -2/9

2 answers:

5 0

Dividing two fractions is the same as multiplying the first fraction by the reciprocal (inverse) of the second fraction.

Take the reciprocal of the second fraction by flipping the numerator and denominator, leaving the negative sign on the numerator, and changing the operation to multiplication. Then the equation becomes

For fraction multiplication, multiply the numerators and then multiply the denominators to get

This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 9 and 12 using

Phoenix [80]3 years ago

4 0

Answer:

Fraction Form: $\frac{3}{4}$ ///// Decimal Form: 0.75

Step-by-step explanation:

Reduce the expression,if possible,by reducing the common factors.

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A girl runs along the sides of a square garden which is 85m long. If she covers 50cm in one step, how many steps will she take t

Blababa [14]

Answer:

850 steps

Step-by-step explanation:

50cm=0.1m

85/0.1=850 steps

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=12x%20%7B%7D%5E%7B3%7D%20%20%5Cdiv%2025x%20%7B%7D%5E%7B5%7D%20" id="TexFormula1" title="12x {}

AleksAgata [21]

Answer:

12x/25

Step-by-step explanation:

i think this is the answer hope its right

6 0

3 years ago

A friend tells you that he has a cubic equation with exactly three complex roots. Determine which explanation best explains why

Ksju [112]

Complex solutions, namely roots with a √(-1) or "i" in it, never come all by their lonesome, because an EVEN root like the square root, can have two roots that will yield the same radicand.

a good example for that will be √(4), well, (2)(2) is 4, so 2 is a root, but (-2)(-2) is also 4, therefore -2 is also a root, so you'd always get a pair of valid roots from an even root, like 2 or 4 or 6 and so on.

therefore, complex solutions or roots are never by their lonesome, their sister the conjugate is always with them, so if there's a root a + bi, her sister a - bi is also coming along too.

if complex solutions come in pairs, well, clearly a cubic equation can't yield 3 only.

3 0

3 years ago

Read 2 more answers

For how many positive values of n are both n3 and 3n four-digit integers?

AVprozaik [17]

Answer:

No positive value of n

Step-by-step explanation:

we have to find out for how many positive values of n are both

$n^3 , 3^n$ our-digit integers

Let us consider first cube

we get 4digit lowest number is 1000 and it has cube root as 10.

Thus 10 is the least integer which satisfies four digits for cube.

The highest integer is 9999 and it has cube root as 21.54

or 21 the highest integer.

Considering 3^n we get,

3^10 is having 5 digits and also 3^21

Thus there is no positive value of n which satisfy that both n cube and 3 power n are four digits.

5 0

4 years ago

Write ninety-eight and one tenth as a decimal number.

deff fn [24]

Answer:

98.1

Step-by-step explanation:

one tenth equates to 0.1

Therefore the answer is 98+0.1=98.1

4 0

3 years ago

Read 2 more answers