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2 years ago

Divide -1/6 divided -2/9

2 answers:

5 0

Dividing two fractions is the same as multiplying the first fraction by the reciprocal (inverse) of the second fraction.

Take the reciprocal of the second fraction by flipping the numerator and denominator, leaving the negative sign on the numerator, and changing the operation to multiplication. Then the equation becomes

For fraction multiplication, multiply the numerators and then multiply the denominators to get

This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 9 and 12 using

Phoenix [80]2 years ago

4 0

Answer:

Fraction Form: $\frac{3}{4}$ ///// Decimal Form: 0.75

Step-by-step explanation:

Reduce the expression,if possible,by reducing the common factors.

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0.1875 rounded to the nearest hundredth

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Which number line correctly shows 1. 5 + 2. 5? A number line going from 0 to 6. 5 in increments of 0. 5. An arrow goes from 0 to

Usimov [2.4K]

So we want to see which number line shows the sum 1.5 + 2.5. We will see that the correct option is "An arrow goes from 0 to 1. 5 and from 1. 5 to 4"

So the number line usually starts at 0 and goes to the first number, 1.5 in this case.

Then, it moves accordingly to the second number, 2.5 (so it will move 2.5 units to the right)

So the number line should start at 0 and move to the right until it meets 1.5 + 2.5 = 4.

From the options, the only that is correct is:

"An arrow goes from 0 to 1. 5 and from 1. 5 to 4"

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2 years ago

Whats the square root of 826 also looking for a minecraft girI needs to be 15 or older

skad [1K]

Answer:

28.740,

Step-by-step explanation:

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3 years ago

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PLEASE HELP 2O POINTS

vovangra [49]

C. The first is a solution, but the second is not.

5x - y/3 = 13 ; (2,-9)
substitute the letters:
5(2) - (-9/3) = 13
10 - (-3) = 13 : note that deducting a number with a negative sign turns both sign as positive.
10 + 3 = 13 ;
13 = 13

5x - y/3 = 13 ; (3,-6)
5(3) - (-6/3) = 13
15 - (-2) = 13
15 + 2 = 13
17 = 13 not equal. not a solution

hope i could help

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3 years ago

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