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Maksim231197 [3]
3 years ago
10

A company manufactures two types of trucks. Each truck must go through the painting shop and the assembly shop. If the painting

shop were completely devoted to painting type 1 trucks, 800 per day could be painted, whereas if the painting shop were completely devoted to painting type 2 trucks, 700 per day could be painted. If the assembly shop were completely devoted to assembling truck 1 engines, 1500 per day could be assembled, whereas if the assembly shop were completely devoted to assembling truck 2 engines, 1200 per day could be assembled. It is possible, however, to paint both types of trucks in the painting shop. Similarly, it is possible to assemble both types in the assembly shop. Each type 1 truck contributes $1000 to profit; each type 2 truck contributes $1500. Use Solver to maximize the company’s profit. (Hint: One approach, but not the only approach, is to try a graphical procedure first and then deduce the constraints from the graph.)
Mathematics
2 answers:
marin [14]3 years ago
8 0

Answer:

Step-by-step explanation:

Nastasia [14]3 years ago
6 0
Because bah. Njhg Biko Higgs yk
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Is 1/2(2p+9)=-p+5 a one solution or infinite solution or no solution​
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Your inequality has one solution which is p = 1/4

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In a missile-testing program, one random variable of interest is the distance between the point at which the missile lands and t
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Step-by-step explanation:

From the given data

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and V=(Y_1^2)+(Y_2)^2 has x^2 with 2 degree of freedom

F_v(v)=\frac{e^{-\frac{v}{2}}}2

Since we have to find the density formula

U=\sqrt{V}

We use method of transformation

h(V)=\sqrt{U}\\\\=U

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We derivate the fuction above with respect to u

\frac{d}{du} (h^-^1(u))=\frac{d}{du} (u^2)\\\\=2u^2^-^1\\\\=2u

Therefore,

F_v(u)=F_v(h-^1)(u)\frac{dh^-^1}{du} \\\\=\frac{e^-\frac{u^-^}{2} }{2} (2u)\\\\=e^-{\frac{u^2}{2} }U

8 0
3 years ago
Solve the equation C=5/9(F-32) Solve for F.
horsena [70]

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Step-by-step explanation:

hope it helps!

4 0
3 years ago
Read 2 more answers
Can somebody help me with this?​
Ghella [55]

Answer:

x=11

Step-by-step explanation:

Since this is a 90º angle, 46º+(4x)º has to equal 90º, and you can make and solve an equation for this:

46+4x=90

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x=11

Check:

46+4x=90

46+4(11)=90

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6 0
3 years ago
Find the value of x and the length of both chords if BW=2x+10, WD=4, CW=7x+5, and WE=2.
daser333 [38]

Answer:

The value of x is 5

The lengths of the chords are 24 units and 42 units

Step-by-step explanation:

In a circle if two chords intersected at a point inside it there are four segments created, two in each cord, the products of the lengths of the line segments on each chord are equal

∵ BD and CE are two chords in a circle intersected at W

∴ The two segments of chord BD are BW and WD

∴ The two segments of chord CE are CW and WE

- By using the rule above

∴ BW × WD = CW × WE

∵ BW = 2x + 10 and WD = 4

∵ CW = 7x + 5 and WE = 2

- Substitute them in the rule above

∴ (2x + 10) × 4 = (7x + 5) × 2

∴ 4(2x) + 4(10) = 2(7x) + 2(5)

∴ 8x + 40 = 14x + 10

- Subtract 14x from both sides

∴ - 6x + 40 = 10

- Subtract 40 from both sides

∴ - 6x = - 30

- Divide both sides by - 6

∴ x = 5

∵ Chord BD = 2x + 10 + 4

∴ Chord BD = 2x + 14

- Substitute the value of x to find its length

∴ Chord BD = 2(5) + 14 = 10 + 14

∴ Chord BD = 24 units

∵ Chord CE = 7x + 5 + 2

∴ Chord CE = 7x + 7

- Substitute the value of x to find its length

∴ Chord CE = 7(5) + 7 = 35 + 7

∴ Chord CE = 42 units

5 0
3 years ago
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