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Stels [109]
3 years ago
7

You have been asked to evaluate two alternatives, X and Y, that may increase plant capacity for manufacturing high-pressure hydr

aulic hoses. The parameters associated with each alternative have been estimated. Which one should be selected on the basis of a present worth comparison at an interest rate of 15% per year? Why is yours the correct choice?
Alternative X Y
First Cost $-45,000 $-58,000
Maintenance cost, per Year $-8000 $-4000
Salvage Value $2,000 $12,000
Life 5 years 5 years

The present worth of alternative X is( ______$ )and that of alternative Y is(_______ $ ).
Business
1 answer:
seraphim [82]3 years ago
7 0

Answer:

Present value of Project X is $41990.6

Present value of Project Y is $34605.2

Explanation:

                           <u>PROJECT X   </u>                                  

PARTICULARS    YEAR      Cost/Value   Present Value factor 15% Present Value

Initial Cost                0              45000         1                  45000

Maintenance           1- 5             8000         3.352           26816

cost

Annual Depreciation 1-5           (8600)       3.352           (28827.2)

Salvage Value              5           (2000)       0.4971         <u> (994.2)    </u>

                      Present value of cash outflows             41,990.6

                             <u>PROJECT Y</u>

<u>PARTICULARS </u>   YEAR   COST/VALUE Present value factor 15% PRESENT VALUE

Initial Cost                 0           58000             1                    58000

Maintenance           1- 5           4000            3.352               13409  

cost

Annual Depreciation  1-5        (9200)           3.352             (30838.4)  

Salvage Value              5         12000            0.4971          <u>  (5965.2) </u>    

Present Value of cash outflow                                          34605.2  

Note: Figures in parenthesis denote cash inflow

Working Notes

Depreciation for project X  = \frac{45000\ -\ 2000}{5}  = $8600 p.a

Depreciation for project Y = \frac{58000\ -\ 12000}{5}  = $9200 p.a

Decision: Since present value of cash outflows is lesser for Project Y, it should be taken up.

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The cost for a carton of milk is $3, and it is sold for $5. When the milk expires, it is thrown out. You also know that the mean
svetlana [45]

Answer:

a) $3

b) $2

c) 1449

Explanation:

Given:

The cost for a carton of milk = $3

Selling price for a carton of milk = $5

Salvage value = $0        [since When the milk expires, it is thrown out ]3

Mean of historical monthly demand = 1,500

Standard deviation = 200

Now,

a) cost of overstocking = Cost  for a carton of milk - Salvage value

= $3 - $0

= $3

cost of under-stocking = Selling price - cost for a carton of milk

= $5 - $3

= $2

b)  critical ratio = \frac{\textup{cost of under-stocking }}{\textup{cost of overstocking + cost of under-stocking }}

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critical ratio = \frac{\textup{2}}{\textup{3 + 2}}

or

critical ratio = 0.4

c) optimal quantity of milk cartons = Mean + ( z × standard deviation )

here, z is the z-score for the critical ration of 0.4

we know

z-score(0.4) = -0.253

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4 0
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The ledger of Shamrock, Inc. on March 31, 2017, includes the following selected accounts before adjusting entries.
romanna [79]

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The adjusting entries are as follows:

1 Insurance expense Dr $310

           To Prepaid Insurance  $310

(Being insurance expense is recorded)  

2 Supplies expense Dr $1,650 ($2,610 - $960)

           To Supplies $1,650

(Being supplies expense is recorded)  

3 Depreciation expense Dr $150

           To Accumulated Depreciation - Equipment $150

(Being depreciation expense is recorded)  

4 Unearned service revenue Dr (two-fifth of $12,000) $4,800

           To Service Revenue $4,800

(Being service revenue is recorded)

3 0
3 years ago
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