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ladessa [460]
3 years ago
8

Please help me I really need help

Mathematics
1 answer:
Dvinal [7]3 years ago
4 0

Answer:

5

7

9

11

13

Step-by-step explanation:

u just have to plot the x values into the x variable if that makes sense

here is an exampla

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4. Which ordered pair is a solution of 3y + 2 = 2x - 5?
Lyrx [107]

Answer:

we determine that none of the ordered pair is a solution of  3y\:+\:2\:=\:2x\:-\:5  as none of the ordered pairs satisfy the equation.

Step-by-step explanation:

Considering the equation

3y\:+\:2\:=\:2x\:-\:5

  • Putting (-5,2) in the equation

3y\:+\:2\:=\:2x\:-\:5

3\left(2\right)\:+\:2\:=\:2\left(-5\right)\:-\:5

8=-15         ∵ L.H.S ≠ R.H.S

FALSE

  • Putting (0,-5) in the equation

3y\:+\:2\:=\:2x\:-\:5

3\left(-5\right)\:+\:2\:=\:2\left(0\right)\:-\:5

-13=-5       ∵ L.H.S ≠ R.H.S

FALSE

  • Putting (5,1) in the equation

3y\:+\:2\:=\:2x\:-\:5

3\left(1\right)+\:2\:=\:2\left(5\right)-\:5

5\:=-5          ∵ L.H.S ≠ R.H.S

FALSE

  • Putting (7,5) in the equation

3y\:+\:2\:=\:2x\:-\:5

3\left(5\right)+\:2\:=\:2\left(7\right)-\:5\:\:

17=9          ∵ L.H.S ≠ R.H.S

FALSE

From the above calculations, we determine that none of the ordered pair is a solution of  3y\:+\:2\:=\:2x\:-\:5  as none of the ordered pairs satisfy the equation.

4 0
3 years ago
The solution of the equation 5-2x=-4x-7 is?​
butalik [34]

Answer: x=-6

Step-by-step explanation:

5-2x=-4x-7

5+2x=-7

2x=-12

X=-6

8 0
3 years ago
How many ounces of gold are in a 16​-karat gold chain that weighs 2.6 ​ounces?
oksano4ka [1.4K]

A 16 karat gold means that there are 16 parts of gold in 24 parts of the gold chain. Therefore the weight of the pure gold is:

pure gold = (16 / 24) * 2.6 ounces

<span>pure gold = 1.73 ounces</span>

7 0
3 years ago
Select the correct answer from each drop-down menu.
yaroslaw [1]
The length of the bigger piece is 28 and the total length is 40
7 0
2 years ago
SALE 70% off
Molodets [167]

Answer:

198.00

Step-by-step explanation:

I am not sure but I hope this helps some.

8 0
3 years ago
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