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evablogger [386]

3 years ago

7

Justify which of the following equations is a quadratic equation. If the equation is quadratic what is the value of a, b & c

. a) 6x3 - 11x – 35 = 0

1 answer:

White raven [17]3 years ago

8 0

Answer:

x=5

Step-by-step explanation:

18x-11x-35=0

7x-35=0

7x=35

x=5

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Suppose y = 48 + 3(2n - 1) is an explicit representation of an arithmetic sequence for integer values n ≥ 1. Find the xth partia

omeli [17]

$a_n=48+3(2n-1)$

The formula of the sum of the arithmetic sequence:
$S_n=\dfrac{a_1+a__n}{2}\cdot n$
calculate:
$a_1=48+3(2\cdot1-1)=48+3=51$
substitute
$S_n=\dfrac{51+48+3(2n-1)}{2}\cdot n=\dfrac{99+6n-3}{2}\cdot n=\dfrac{96+6n}{2}\cdot n=3n^2+48n$
Your answer is:
$\boxed{f(x)=3x^2+48x}$

5 0

3 years ago

Read 2 more answers

can someone please help me with this question!!

valkas [14]

Answer:

B' (-4, -4)

Step-by-step explanation:

When you dilate from the origin, you multiply the coordinate points by the scale factor.

B (-1, -1) × 4 = B' (-4, -4)

I hope this helps :))

7 0

3 years ago

Zeus Industries bought a computer for $2730. It is expected to depreciate at a rate of 30% per year. What will the value of the

Lostsunrise [7]

The price will be $655.47 after four years

6 0

3 years ago

Which of the following is the equation of a circle that has a radius of 2.5 and its center at (4, -3)?

Oxana [17]

The answer should be:

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4 0

3 years ago

Your friend says that the absolute value equation |3x+8|−9=−5 has no solution because the constant on the right side of the equa

xenn [34]

$Solution, solve\:for\:x,\:\left|3x+8\right|-9=-5\quad :\quad x=-4\quad \mathrm{or}\quad \:x=-\frac{4}{3}$

$Steps:$

$\left|3x+8\right|-9=-5$

$\mathrm{Add\:}9\mathrm{\:to\:both\:sides},\\\left|3x+8\right|-9+9=-5+9$

$\mathrm{Simplify},\\\left|3x+8\right|=4$

$|f\left(x\right)|=a\quad \Rightarrow \:f\left(x\right)=-a\quad \mathrm{or}\quad \:f\left(x\right)=a,\\3x+8=-4\quad \quad \mathrm{or}\quad \:\quad \:3x+8=4$

$3x+8=-4,\\\mathrm{Subtract\:}8\mathrm{\:from\:both\:sides},\\3x+8-8=-4-8,\\\mathrm{Simplify},\\3x=-12,\\\mathrm{Divide\:both\:sides\:by\:}3,\\\frac{3x}{3}=\frac{-12}{3},\\\mathrm{Simplify},\\x=-4$

$3x+8=4,\\\mathrm{Subtract\:}8\mathrm{\:from\:both\:sides},\\3x+8-8=4-8,\\\mathrm{Simplify},\\3x=-4,\\\mathrm{Divide\:both\:sides\:by\:}3,\\\frac{3x}{3}=\frac{-4}{3},\\\mathrm{Simplify},\\x=-\frac{4}{3}$

$Combine\:the\:ranges,\\x=-4\quad \mathrm{or}\quad \:x=-\frac{4}{3}$

$\mathrm{The\:Correct\:Answer\:is\:No\:They\:Are\:Not\:Correct}$

$\mathrm{Hope\:This\:Helps!!!}$

$\mathrm{-Austint1414}$

4 0

3 years ago