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evablogger [386]
3 years ago
7

Justify which of the following equations is a quadratic equation. If the equation is quadratic what is the value of a, b & c

. a) 6x3 - 11x – 35 = 0
Mathematics
1 answer:
White raven [17]3 years ago
8 0

Answer:

x=5

Step-by-step explanation:

18x-11x-35=0

7x-35=0

7x=35

x=5

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If y varies jointly as x and z and y = 4 when x = 2 and z = 3, what is y when x = -6 and z = 2?
sp2606 [1]

Answer:

Step-by-step explanation:

Y = kxz

Putting values of y x and z in the equation

4 = k(2)(3)

4 = k6

2/3 = k

Now finding y when x = - 6 and z = 2

Y = kxz

= 2/3(-6)(2)

= - 8

3 0
3 years ago
M is the midpoint of the segment. Find the length of XM.
Lelechka [254]

Answer:

x=2 and XM=11

Step-by-step explanation:

because M is the midpoint of the line, you know that both XM and ZM are equal and you know an expression for the lengths of both of these.

set these expressions equal and solve:

4x+3=3x+5 so by subtracting the 3x from the right side, moving it over to the left and subtracting 3 from the left side to move it over to the right, you get:

x=2

then to find XM, plug in this value of x to get XM=11

4(2)+3=11

4 0
2 years ago
Farmer Janet can plant 9 feet of carrots in 15 minutes while her daughter Amy can plant 17 feet of carrots in half an hour. what
lorasvet [3.4K]

Answer:

janet can plant 36 per hour Amy can plant 34per hour

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Dan buys a car for £1700.
aleksley [76]

Answer:

£1443.89

Step-by-step explanation:

To start you take the £1700 and multiply it by 4% (or .04) to find how much it depreciates for the first year. For the first year the depreciation £68 so the next year it will be worth £1632 ( £1700 - 68). You do the same thing for the second year but you start with the amount its worth now (£1632) and multiply again by the 4%. The depreciation for the second year is 65.28. Now you take what it was worth at the start of the year (£1632) and subtract the depreciation for the second year (65.28) to get £1566.72. You do the same process again for the third year to end up with a value of £1504.05. Now for the 4th year you will take the value of £1504.05 and again multiply by the depreciation rate of 4% to find the last amount of depreciation which is £60.16. Take your starting value for year 4 (£1504.05) and subtract the amount of depreciation (£60.16) to get your answer of £1443.89.

4 0
3 years ago
.
KATRIN_1 [288]

Answer:-77

Step-by-step explanation:positive plus a negative equal a negative unless the negative is smaller then the number you subtract it from

4 0
3 years ago
Read 2 more answers
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