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ozzi
3 years ago
14

What is the sum of the arithmetic sequence 3, 9, 15…, If there are 34 terms?

Mathematics
1 answer:
snow_tiger [21]3 years ago
6 0

Answer:

first we find the common difference.....do this by subtracting the first term from the second term. (9 - 3 = 6)...so basically, ur adding 6 to every number to find the next number.

we will be using 2 formulas....first, we need to find the 34th term (because we need this term for the sum formula)

an = a1 + (n-1) * d

n = the term we want to find = 34

a1 = first term = 3

d = common difference = 6

now we sub

a34 = 3 + (34-1) * 6

a34 = 3 + (33 * 6)

a34 = 3 + 198

a34 = 201

now we use the sum formula

Sn = (n (a1 + an)) / 2

S34 = (34(3 + 201))/2

s34 = (34(204)) / 2

s34 = 6936/2

s34 = 3468 <=== the sum of the first 34 terms:

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I will try to solve your system of equations.

y=22;−10x+15y=−10

Step: Solvey=22for y:

Step: Substitute22foryin−10x+15y=−10:

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−10x+(15)(22)=−10

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−10x+330+−330=−10+−330(Add -330 to both sides)

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(Divide both sides by -10)

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Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

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