Answer:
3
Step-by-step explanation:
Given the data: 7 6 5 9 3 4 7 9 5 8
INTERQUARTILE RANGE (IQR) = Q3 - Q1
Rearranging the data: 3, 4, 5, 5, 6, 7, 7, 8, 9, 9
Q3 = 0.75(n+1)th term
Q3 = 0.75(10 + 1) th term
Q3 = 0.75(11)th term = 8.25th term
Taking the 8th term = 8
Q1 = 0.25(11)th term = 2.75th
Taking the average of the 8th and 9th term:
(5 + 5) / 2 = 10/2 = 5
Q3 - Q1 = (8 - 5) = 3
It is 10 times greater because
10x10=100
Answer: -7cos(x)
Step-by-step explanation:
d/dx (f(x))= -7cos(x)
Answer:
The 80% confidence interval for the the population mean nitrate concentration is (0.144, 0.186).
Critical value t=1.318
Step-by-step explanation:
We have to calculate a 80% confidence interval for the mean.
The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.
The sample mean is M=0.165.
The sample size is N=25.
When σ is not known, s divided by the square root of N is used as an estimate of σM:
The degrees of freedom for this sample size are:
The t-value for a 80% confidence interval and 24 degrees of freedom is t=1.318.
The margin of error (MOE) can be calculated as:
Then, the lower and upper bounds of the confidence interval are:
The 80% confidence interval for the population mean nitrate concentration is (0.144, 0.186).
Volume is L x W x H
8 x 10 x 3 = 240 cubic units