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shutvik [7]
3 years ago
6

Pass through (1,2) and (3,1)

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
7 0

Answer:

y=-\frac{1}{2}x+\frac{5}{2}

Step-by-step explanation:

slope = -1/2

y - int. = 5/2

<em>good luck, i hope this helps :)</em>

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4 years ago
Assume that when adults with smartphones are randomly​ selected, 46​% use them in meetings or classes. If 9 adult smartphone use
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Answer:

0.18173219.

Step-by-step explanation:

We have been asked to find what will be the probability that at least 6 of 9 adults use their smartphones in meetings or classes.

We will find our answer using Bernoulli's trails.

_{r}^{n}\textrm{c}\cdot p^{r}\cdot (1-p)^{n-r}

First of all we will find the probabilities when r is 6, 7,8 and 9 then we will add them all.

When r=6,

_{6}^{9}\textrm{c}\cdot 0.46^{6}\cdot (1-0.46)^{9-6}

\frac{9!}{6!3!} *0.46^{6} *0.54^{3}

\frac{9*8*7*6!}{6!*3*2*1} *0.009474296896*0.157464

84*0.009474296896*0.157464=0.12532

Similarly we will find Probabilities when r=7, 8 and 9.

When r=7

_{7}^{9}\textrm{c}\cdot 0.46^{7}\cdot (1-0.46)^{9-7}

\frac{9!}{7!2!} *0.46^{7} *0.54^{2}

\frac{9*8*7!}{7!*2*1} *0.00435817657216*0.2916

36*0.00435817657216*0.2916=0.04575039

When r=8

_{8}^{9}\textrm{c}\cdot 0.46^{8}\cdot (1-0.46)^{9-8}

\frac{9!}{8!1!} *0.46^{8} *0.54

\frac{9*8!}{8!*1!} *0.00200476*0.54

9 *0.00200476*0.54=0.0097431336

When r=9,

_{9}^{9}\textrm{c}\cdot 0.46^{9}\cdot (1-0.46)^{9-9}

\frac{9!}{9!0!} *0.46^{9} *1

1 *0.00092219*1=0.00092219

Now let us add all the probabilities to get the final answer.

0.12532+0.04575+0.00974+0.00092219=0.18173219

Therefore, probability that at least 6 of 9 adults use their smartphones in meetings or classes is 0.18173219.

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