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Tanzania [10]
3 years ago
5

The difference of d minus 3 divided by 2​

Mathematics
2 answers:
Novay_Z [31]3 years ago
5 0

Answer:

(d-3) /2. If this is an equation, then you need to know what d is. If it is an expression, I just gave you the answer

Step-by-step explanation:

zlopas [31]3 years ago
4 0

Answer:

\frac{d-3}{2}

Step-by-step explanation:

d minus 3 : d - 3

d -3  divide by 2:  \frac{d - 3 }{2}

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Triangle $ABC$ with vertices of $A(6,2)$, $B(2,5)$, and $C(2,2)$ is reflected over the x-axis to triangle $A'B'C'$. This triangl
SCORPION-xisa [38]

Answer:

  C''(-2, -2)

Step-by-step explanation:

Reflection over the x-axis negates the y-coordinate. Reflection over the y-axis negates the x-coordinate. Negating both coordinates of C(2, 2) makes it ...

  C''(-2, -2)

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%284y%20%2B%204x%29%20%3D%20" id="TexFormula1" title="(4y + 4x) = " alt="(4y + 4x) = " align="
Semmy [17]
<span> Simplifying
4x + 4y = 0

 Solving
4x + 4y = 0

 Solving for variable 'x'.
 Move all terms containing x to the left, all other terms to the right.

 Add '-4y' to each side of the equation.
4x + 4y + -4y = 0 + -4y

 Combine like terms:
4y + -4y = 0
4x + 0 = 0 + -4y
4x = 0 + -4y

 Remove the zero:
4x = -4y

 Divide each side by '4'.
x = -1y

 Simplifying
x = -1y</span>
8 0
4 years ago
Please help with this and explain how to do it, I'll give 15 points
MrRissso [65]

Answer:

Option (4).

Step-by-step explanation:

Outer diameter of the hollow metallic ball = 10 centimeters

Outer radius of this ball = \frac{10}{2} = 5 cm

Volume of the outer ball V_{1} = \frac{4}{3}\pi (r)^3

                                         = \frac{4}{3}\pi (5)^3

Inner radius of the hollow metallic ball = (5 - 1) = 4 cm

Volume of the inner hollow ball V_{2} = \frac{4}{3}\pi (4)^3

Volume of the metal used in the metallic ball = V_{1}-V_{2}

                                                                           = \frac{4}{3}\pi (5)^3-\frac{4}{3}\pi (4)^{3}

                                                                           = \frac{4}{3}\pi [(5)^3-(4)^3]

Therefore, expression given in option (4) will be used to measure the volume of the hollow metallic ball.

8 0
3 years ago
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