Answer:
Step-by-step explanation:
#8
step #1: <em><u>add $24.94 with $3.82</u></em>
24.94 + 3.82 = 28.76
Step #2: <u><em>subtract </em></u>
$50 - 28.76 = <u>$21.24</u>
Answer:
Step-by-step explanation:
-7z/2 - 2 + z -3
=-5 - 5z/2
Answer:
Check Explanation.
Step-by-step explanation:
The sample will be a representative of the entire build us in the city.
For a sample size 35, 3 have fire code violations, hence, the proportion of houses with fire code violations = (3/35) = 0.0857 = 8.57 %
The uncertainty in the estimate is given in the form of standard error.
Standard error = √[(p(1-p)/n]
n = sample size = 35, p = 0.0857, 1 - p = 0.9143
Standard error of the sample = √(0.0857×0.9143/35) = 0.1616
In terms of the population, (0.1616/35) = 0.00462
Proportion of buildings with fire code violations = (8.57 ± 0.462) %
Complete question is:
Seventy million pounds of trout are grown in the U.S. every year. Farm-raised trout contain an average of 32 grams of fat per pound, with a standard deviation of 7 grams of fat per pound. A random sample of 34 farm-raised trout is selected. The mean fat content for the sample is 29.7 grams per pound. Find the probability of observing a sample mean of 29.7 grams of fat per pound or less in a random sample of 34 farm-raised trout. Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places.
Answer:
Probability = 0.0277
Step-by-step explanation:
We are given;
Mean: μ = 32
Standard deviation;σ = 7
Random sample number; n = 34
To solve this question, we would use the equation z = (x - μ)/(σ/√n) to find the z value that corresponds to 29.7 grams of fat.
Thus;
z = (29.7 - 32)/(7/√34)
Thus, z = -2.3/1.200490096
z = -1.9159
From the standard z table and confirming with z-calculator, the probability is 0.0277
Thus, the probability to select 34 fish whose average grams of fat per pound is less than 29.7 = 0.0277
