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2 years ago

5. How many tenths are in 2 2/10

Mathematics

1 answer:

Neko [114]2 years ago

6 0

Answer:

2 tenths

Step-by-step explanation:

In decimal form: 2.2

You can see that in the tenths place, there is a 2, so 2 tenths.

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Joe studied math for x minutes, and then studied Spanish for 20 minutes more than he studied math. He did this for 3 days in a r

never [62]

Answer:

x+20 * 3

Step-by-step explanation:

* represents a multiplication symbol

3 0

2 years ago

Type 11/5 in the simplest form

aleksklad [387]

Answer:

$2\frac{1}{5}$

Step-by-step explanation:

11 ÷ 5 = 2 R 1 → $2\frac{1}{5}$

Hope this helps! :)

7 0

2 years ago

The resting heart rate of an adult is usually about 60 beats per minute. Use your completed table to find approximately how many

Dvinal [7]

60x=1,000,000
----- ---------------
60 60
X=16,666 2/3 or
X=16,666.6667 it would take approximately 16,667 minutes for the average resting heart to beat 1,000,000 times.

3 0

2 years ago

Suppose there are 4 defective batteries in a drawer with 10 batteries in it. A sample of 3 is taken at random without replacemen

SSSSS [86.1K]

Answer:

a.) 0.5

b.) 0.66

c.) 0.83

Step-by-step explanation:

As given,

Total Number of Batteries in the drawer = 10

Total Number of defective Batteries in the drawer = 4

⇒Total Number of non - defective Batteries in the drawer = 10 - 4 = 6

Now,

As, a sample of 3 is taken at random without replacement.

a.)

Getting exactly one defective battery means -

1 - from defective battery

2 - from non-defective battery

So,

Getting exactly 1 defective battery = ⁴C₁ × ⁶C₂ = $\frac{4!}{1! (4 - 1 )!}$ × $\frac{6!}{2! (6 - 2 )!}$

= $\frac{4!}{(3)!}$ × $\frac{6!}{2! (4)!}$

= $\frac{4.3!}{(3)!}$ × $\frac{6.5.4!}{2! (4)!}$

= $4$ × $\frac{6.5}{2.1! }$

= $4$ × $15$ = 60

Total Number of possibility = ¹⁰C₃ = $\frac{10!}{3! (10-3)!}$

= $\frac{10!}{3! (7)!}$

= $\frac{10.9.8.7!}{3! (7)!}$

= $\frac{10.9.8}{3.2.1!}$

= 120

So, probability = $\frac{60}{120} = \frac{1}{2} = 0.5$

b.)

at most one defective battery :

⇒either the defective battery is 1 or 0

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 0 , then 3 non defective

Possibility = ⁴C₀ × ⁶C₃

= $\frac{4!}{0! (4 - 0)!}$ × $\frac{6!}{3! (6 - 3)!}$

= $\frac{4!}{(4)!}$ × $\frac{6!}{3! (3)!}$

= 1 × $\frac{6.5.4.3!}{3.2.1! (3)!}$

= 1× $\frac{6.5.4}{3.2.1! }$

= 1 × 20 = 20

getting at most 1 defective battery = 60 + 20 = 80

Probability = $\frac{80}{120} = \frac{8}{12} = 0.66$

c.)

at least one defective battery :

⇒either the defective battery is 1 or 2 or 3

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 2 , then 1 non defective

Possibility = ⁴C₂ × ⁶C₁

= $\frac{4!}{2! (4 - 2)!}$ × $\frac{6!}{1! (6 - 1)!}$

= $\frac{4!}{2! (2)!}$ × $\frac{6!}{1! (5)!}$

= $\frac{4.3.2!}{2! (2)!}$ × $\frac{6.5!}{1! (5)!}$

= $\frac{4.3}{2.1!}$ × $\frac{6}{1}$

= 6 × 6 = 36

If the defective battery is 3 , then 0 non defective

Possibility = ⁴C₃ × ⁶C₀

= $\frac{4!}{3! (4 - 3)!}$ × $\frac{6!}{0! (6 - 0)!}$

= $\frac{4!}{3! (1)!}$ × $\frac{6!}{(6)!}$

= $\frac{4.3!}{3!}$ × 1

= 4×1 = 4

getting at most 1 defective battery = 60 + 36 + 4 = 100

Probability = $\frac{100}{120} = \frac{10}{12} = 0.83$

3 0

2 years ago

John kept track of how many baskets were made in a basketball game. After 4 minutes, 5 baskets were made.

ivann1987 [24]

1 basket is between 9 and 10 minutes .

<u>Step-by-step explanation:</u>

Here we have , John kept track of how many baskets were made in a basketball game. After 4 minutes, 5 baskets were made. We need to find How many baskets were made between 9 and 10 minutes . Let's find out:

In order to calculate baskets between 9 min and 10 min we will find baskets at 10 min and at at 9 min , will subtract than !

Baskets at 10 min :

At 4 min we have 5 baskets so , in 10 min

⇒ $(10)\frac{5}{4}$