Answer:
62.17% probability that a randomly selected exam will require more than 15 minutes to grade
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the probability that a randomly selected exam will require more than 15 minutes to grade
This is 1 subtracted by the pvalue of Z when X = 15. So
has a pvalue of 0.3783.
1 - 0.3783 = 0.6217
62.17% probability that a randomly selected exam will require more than 15 minutes to grade
D has a value of 24.
V121 is 11, so 13 + 11 is 24
Answer:
Step-by-step explanation:
Answer: $65.50 - 15% = 55.675
Step-by-step explanation:
Conversion a decimal number to a fraction: 65.50 = 655
10
= 131
2
Conversion a decimal number to a fraction: 9.825 = 9825
1000
= 393
40
Subtract: 65.5 - 9.825 = 131
2
- 393
40
= 131 · 20
2 · 20
- 393
40
= 2620
40
- 393
40
= 2620 - 393
40
= 2227
40
The common denominator you can calculate as the least common multiple of the both denominators - LCM(2, 40) = 40
Answer:
Answers may vary but will most likely be close to 2.
Step-by-step explanation
- Given:
first test:38%
second test:76%
SIMULATION FIRST TEST
Randomly select a 2-digit number.
If the digit is between 00 and 35 then you passed the test,else you did not pass the test.
SIMULATION SECOND TEST
Randomly select a 2-digit number.
if the digit is between 00 and 75 then you passed the test,else you did not pass the test.
SIMULATION TRIAL
Perform the simulation of the first test.if you did not pass the first test then perform the simulation of the second test.
Record the number of trials needed to pass the first or second test.
Repeat 20 times and take the average of the 20 recorded number of trials
(what is the sum of recorded values divided by 20).
Note:you will most likely obtain a result of about two trials needed.
