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harina [27]
4 years ago
5

What is 628 times 33 with work shown

Mathematics
1 answer:
Anarel [89]4 years ago
3 0
628
x33
1884
+18840
20724 <- answer
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I don’t get this question
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In 195019501950, the per capita gross domestic product (GDP) of Australia was approximately \$1800$1800dollar sign, 1800. Each y
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Answer:

The function of capita GDP is given by

G(t)= 1800(1+0.067)^t

where G(t) is in dollar and t is years after 1950.

Step-by-step explanation:

Given that,

in 1950, the per capita GDP of Australia was $1800.

The capita GDP is increased by 6.7 % per year.

In 1951, the capita GDP was increased =6.7% of $1800

The capita GDP was= $1800+ 6.7% of $1800

                                 =$1800(1+6.7%)

In 1952, the capita GDP was increased =$1800(1+6.7%)

The capita GDP was=$1800(1+6.7%)+ 6.7% of$1800(1+6.7%)

                                 =$1800(1+6.7%)(1+6.7)

                                 = $1800(1+6.7%)²

                                 =$1800(1+0.067)²

In 1952, the capita GDP was increased =$1800(1+6.7%)²

The capita GDP was=$1800(1+6.7%)²+ 6.7% of$1800(1+6.7%)²

                                 =$1800(1+6.7%)²(1+6.7)

                                 = $1800(1+6.7%)³

                                  =$1800(1+0.067)³

and so on.

The function of capita GDP is given by

G(t)= 1800(1+0.067)^t

where G(t) is in dollar and t is years after 1950.

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In this question, we are given the following:

Step 2:

The details of the solution are as follows:

Step 3:

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