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3 years ago

An observer stationed 20 m away from a tall

Mathematics

2 answers:

antiseptic1488 [7]3 years ago

5 0

Answer:

Step-by-step explanation:I don't say you must have to mark my ans as brainliest but my friend if it has really helped you plz don't forget to thank me...

Nimfa-mama [501]3 years ago

4 0

Alazgggggg akstafarrrallaa ?

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We would like to create a confidence interval.

Vlada [557]

Answer:

c.A 90% confidence level and a sample size of 300 subjects.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level $1-\alpha$ , we have the confidence interval with a margin of error of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

In this problem

The proportions are the same for all the options, so we are going to write our margins of error as functions of $\sqrt{\pi(1-\pi)}$

a.A 99% confidence level and a sample size of 50 subjects.

$n = 50$

99% confidence interval

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{2.575}{\sqrt{50}}\sqrt{\pi(1-\pi)} = 0.3642\sqrt{\pi(1-\pi)}$

b.A 90% confidence level and a sample size of 50 subjects.

$n = 50$

90% confidence interval

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{1.645}{\sqrt{50}}\sqrt{\pi(1-\pi)} = 0.2623\sqrt{\pi(1-\pi)}$

c.A 90% confidence level and a sample size of 300 subjects.

$n = 300$

90% confidence interval

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{1.645}{\sqrt{300}}\sqrt{\pi(1-\pi)} = 0.0950\sqrt{\pi(1-\pi)}$

This produces smallest margin of error.

d.A 99% confidence level and a sample size of 300 subjects.

$n = 300$

99% confidence interval

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{2.575}{\sqrt{300}}\sqrt{\pi(1-\pi)} = 0.1487\sqrt{\pi(1-\pi)}$

6 0

4 years ago

Copy and complete the statement using <,> or =.

Veronika [31]

I did not understand

6 0

3 years ago

Find the solutions of the form x=a,y=0and x=0 ,y=b for the following equations: 2x+5y=10 and 2x+3y=6. is there any common soluti

Arlecino [84]

Answer:

x=0 and y=2

Step-by-step explanation:

We have been given system of equations:

2x+5y=10 (1)

And 2x+3y=6 (2)

Subtract equation (2) from(1) we get:

2y=4

y=2

Now, substitute y=2 in equation(2) we get:

2x+3(2)=6

2x+6=6

2x=0

x=0

Hence, x=0 and y=2

8 0

3 years ago

For each of parts (a) through (d), indicate whether we would generally expect the performance of a flexible statistical learning

olga_2 [115]

Step-by-step explanation:

First, note that a flexible statistical learning method refers to using models that take into account agree difference in the observed data set, and are thus adjustable. While the inflexible method usually involves a model that has no regard to the kind of data set.

a) The sample size n is extremely large, and the number of predictors p is small. (BETTER)

In this case since the sample size is extremely large a flexible model is a best fit.

b) The number of predictors p is extremely large, and the number of observations n is small. (WORSE)

In such case overfiting the data is more likely because of of the small observations.

c) The relationship between the predictors and response is highly non-linear. (BETTER)

The flexible method would be a better fit.

d) The variance of the error terms, i.e. σ2=Var(ϵ), is extremely high. (WORSE)

In such case, using a flexible model is a best fit for the error terms because it can be adjusted.

6 0

3 years ago

The term coefficient refers to

Dmitry_Shevchenko [17]

Answer:

It refers to a numerical or constant quantity placed before and multiplying the variable in an algebraic expression.

5 0

3 years ago