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nasty-shy [4]
3 years ago
9

PLZ HELP NOW (3^4)/(3^x)=27 what is x

Mathematics
2 answers:
Illusion [34]3 years ago
4 0

Answer:

x = 1

Step-by-step explanation:

Create equivalent expressions in the equation that all have equal bases, then solve for  x.  

x = 1

Hope this helped

cricket20 [7]3 years ago
3 0
The answer to your question is x=1
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How to prove tan z is analytic using cauchy-riemann conditions
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A function f(z)=f(x+iy)=u(x,y)+i v(x,y) is analytic if the C-R conditions are satisfied:

\begin{cases}u_x=v_y\\u_y=-v_x\end{cases}

We have

f(z)=\tan z=\tan(x+iy)

Recall the angle sum formula for tangent:

\tan(x+iy)=\dfrac{\tan x+\tan iy}{1-\tan x\tan iy}

Now recall that

\tan iy=\dfrac{\sin iy}{\cos iy}=\dfrac{-\frac{e^y-e^{-y}}{2i}}{\frac{e^y+e^{-y}}2}=\dfrac{i\sinh y}{\cosh y}=i\tanh y

So we have

\dfrac{\tan x+\tan iy}{1-\tan x\tan iy}=\dfrac{\tan x+i\tanh y}{1-i\tan x\tanh y}
=\dfrac{(\tan x+i\tanh y)(1+i\tan x\tanh y)}{(1-i\tan x\tanh y)(1+i\tan x\tanh y)}
=\dfrac{\tan x+i\tanh y+i\tan^2x-\tan x\tanh^2y}{1+\tan^2x\tanh^2y}
=\dfrac{\tan x(1-\tanh^2y)}{1+\tan^2x\tanh^2y}+i\dfrac{\tanh y(1+\tan^2x)}{1+\tan^2x\tanh^2y}
=\underbrace{\dfrac{\tan x\sech^2y}{1+\tan^2x\tanh^2y}}_{u(x,y)}+i\underbrace{\dfrac{\tanh y\sec^2x}{1+\tan^2x\tanh^2y}}_{v(x,y)}

We could stop here, but taking derivatives may be messy and would be easier to do if we can write this in terms of sines and cosines.

u(x,y)=\dfrac{\tan x\sech^2y}{1+\tan^2x\tanh^2y}=\dfrac{\frac{\sin x}{\cos x\cosh^2x}}{1+\frac{\sin^2x\sinh^2y}{\cos^2x\cosh^2y}}=\dfrac{\sin x\cos x}{\cos^2x\cosh^2y+\sin^2x\sinh^2y}
u(x,y)=\dfrac{\sin2x}{2\cos^2x\cosh^2y+2(1-\cos^2x)(\cosh^2y-1)}=\dfrac{\sin2x}{2\cosh^2y-1+2\cos^2x-1}
u(x,y)=\dfrac{\sin2x}{\cos2x+\cosh2y}

With similar usage of identities, we can find that

v(x,y)=\dfrac{\sinh2y}{\cos2x+\cosh2y}

Now we check the C-R conditions.

u_x=\dfrac{2\cos2x(\cos2x+\cosh2y)-(-2\sin2x)\sin2x}{(\cos2x+\cosh2y)^2}=\dfrac{2+2\cos2x\cosh2y}{(\cos2x+\cosh2y)^2}
v_y=\dfrac{2\cosh2y(\cos2x+\cosh2y)-(2\sinh2y)\sinh2y}{(\cos2x+\cosh2y)^2}=\dfrac{2+2\cosh2y\cos2x}{(\cos2x+\cosh2y)^2}
\implies u_x=v_y

Similarly, you can check that u_y=-v_x, hence the C-R conditions are satisfied, and so \tan z is analytic.
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7g:1kg to its simplest form​
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Suzanne bought 50 apples at the apple orchard. She bought 4 times as many red apples as green apples. How many more red apples t
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Let x = the number of green apples, let 4x = the number of red apples
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