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2 years ago

If there are 5380 feet in a mile Express 4000 get In kilometersplease show how you go it

Mathematics

1 answer:

mariarad [96]2 years ago

7 0

Answer:

ok first there is a problem here there are actually 5280 NOT 5380 feet in a mile. Is this a typo or are you to assume a different length of a mile?

I will stick with the real value of 5280...

5280 feet/ mile * 0.62137119 miles/ km = 3280 f/km

3280 f/km / 4000 feet = .82 km

Step-by-step explanation:

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What is the solution set of these system5x-2y=17 and 4x-7=13?

MatroZZZ [7]

Answer:

x=5

y=4

Step-by-step explanation:

Step 1:

Let us solve for x using the $4x-7=13$ equation by isolating terms containing the variable:

$4x-7=13\\4x=20\\\fbox{x=5}$

Great! x is 5... let's find y.

Step 2:

Since we know the value of x, we can use what we know to find y using the other equation:

$5x-2y=17\\$

Given that x=5, we can replace x with 5.

$5*5-2y=17\\25-2y=17\\2y=8\\\\\fbox{y=4}$

I hope this helps! Let me know if you have any questions :)

3 0

2 years ago

J.k. Rowling and R.L. Stone are both ready hunger games . J.k. Reads 35 pages every 2 hours and R.L. Reads 45 pages every 3 hour

san4es73 [151]

Answer:

The rate of change for each reader is :

For J K Rowling : 17 and a half pages per hour

For R L Stone : 15 pages per hour

Step-by-step explanation:

Here the reading rate of each reader is given as:

J.K. Reads 35 pages every 2 hours.

So, the number of pages read by J K in 2 hours = 35 pages

⇒ The number of pages read per hour = 35 / 2 = 17 . 5 pages

So, the pages read by J K Rowling in 1 hour is 17 and a half pages.

R L Stone reads 45 pages every 3 hours.

So, the number of pages read by R L in 3 hours = 45 pages

⇒ The number of pages read per hour = 45 / 3 = 15 pages

So, the pages read by R L Stone in 1 hour is 15 pages.

Hence, the rate of change for each reader is :

For J K Rowling : 17 and a half pages per hour

For R L Stone : 15 pages per hour

5 0

3 years ago

The planets move around the sun in elliptical orbits with the sun at one focus. The point in the orbit at which the planet is cl

gladu [14]

Consider the attached ellipse. Let the sun be at the right focus. Then perihelion is at right vertex on the x-axis and aphelion is at the left vertex on the x-axis.

The distances:

from perihelion to the sun in terms of ellipse is a-c;
from aphelion to the sun in terms of ellipse is a+c.

Then

$\left\{\begin{array}{l}a-c=741,000,000\\a+c=817,000,000\end{array}\right.$

Add these two equations:

$2a=1,558,000,000 \\ \\a=779,000,000$

and subtract first equation from the second:

$2c=76,000,000 \\ \\c=38,000,000.$

Note that $b=\sqrt{a^2-c^2},$ thus

$b=\sqrt{779,000,000^2-38,000,000^2}=\sqrt{605,397,000,000,000,000}.$

The equation for the planet's orbit is

$\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1\Rightarrow \dfrac{x^2}{606,841,000,000,000,000}+\dfrac{y^2}{605,397,000,000,000,000}=1.$

7 0

3 years ago

A rectangular garden is to be fenced so that one of the sides is 5 feet longer than an adjacent side (s). Which of the following

Sophie [7]

The correct answer is: [B]: " s² + 5s " .
________________________________
A = s(s+5) = s² + 5s ;

→ which is: Answer choice: [B] .
________________________________

3 0

3 years ago

Use the relationship between the angles in the figure to answer the question.

Anuta_ua [19.1K]

Answer:

37+x+53 = 180

x=90

Step-by-step explanation:

To find x, we need to use the fact that a straight line equals 180 degrees.

37+x+53 = 180

Combining like terms

90+x = 180

Subtract 90 from each side

90-90+x = 180-90

x = 90

4 0

3 years ago

Read 2 more answers

If there are 5380 feet in a mile Express 4000 get In kilometersplease show how you go it​

If there are 5380 feet in a mile Express 4000 get In kilometersplease show how you go it