To get rid of

, you have to take the third root of both sides:
![\sqrt[3]{x^{3}} = \sqrt[3]{1}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%5E%7B3%7D%7D%20%3D%20%5Csqrt%5B3%5D%7B1%7D%20)
But that won't help you with understanding the problem. It is better to write

as a product of 2 polynomials:

From this we know, that

is the solution. Another solutions (complex roots) are the roots of quadratic equation.
Answer:
5/hypotenuse, the square root of 7/ leg
Step-by-step explanation:
3^2+4^2=25 or 5^2. you use a^2+b^2=c^2. it would be one of the hypotenuses. If the missing number is a leg, you would do 4^2=3^2+x^2. 16=9+x^2, 7=x^2, so you plug in the numbers differently.
Answer:
4 altogether
0,1 + 1, 1 = 1 RA
0,1 + 2,1 = 1 RA
0.2 +1, 2 = 1 RA
0,2 +2,2 = 1 RA
Step-by-step explanation:
The answer is B i believe