Question

Write an equation of a line containing (2, -3) and perpendicular to 3x+4y=14 answer

Answer 1

Answer:

Step-by-step explanation:

From the condition of perpendicularity, if two lines must be perpendicular to each other, the product of their gradient rather the slope must be equaled to ( -1 ).

Equation of a line ; y = mx+ c, where m1 is the gradient of the line and c us the point of intersection if the line on the y- axis.therefore, the equation

3x + 4y = 14, when re arranged, now becomes, 4y = -3x + 14, divide through by 4, gives, y = -3x/4 + 14.

Therefore, m1, = -3/4 and m2, = 4/3 going by the condition. Since the line passes through the coordinate of (2,3), where x = 2, and y = -3, then, substitute for x and y in y = mx+ c, minding the m2, to find C, therefore,

-3 = 4/3x2 + c. -3 = 8/3 +c

Multiply through by 3 to make it a linear equation,

-9 = 8 + 3c; -9 - 8 = 3c, -17= 3c

c = -17/3.Now substitute for c in the equation ,y = mx+ c, the equation now becomes, y = 4x/3 - 17/3. Therefore the new equation is

3y = -4x - 17.