Ok, so you knnow that for angles to be supplement, they need to equal 180 degrees. So you can create an equation as follows:
(3 times X minus 12) degrees plus (x)degrees equals 180 degrees
(3x-12) + (x)=180
4x-12=180
4x=192
x=48
So now you plug in "x=48" into this equation (3x-12) to find the measure of the angle.
And if I did the math correctly, the answer should be "132" degrees.
Well all u have to do is 156%*70= 109.2 so N= 109.2
90 tens hopefully this helped
Answer:
<h2><em>
38°, 66° and 76°</em></h2>
Step-by-step explanation:
A triangle consists of 3 angles and sides. The sum of the angles in a triangle is 180°. Let the angle be <A, <B and <C.
<A + <B + <C = 180° ...... 1
If the measure of one angle is twice the measure of a second angle then
<A = 2<B ...... 2
Also if the third angle measures 3 times the second angle decreased by 48, this is expressed as <C = 3<B-48............ 3
Substituting equations 2 and 3 into 1 will give;
(2<B) + <B + (3<B-48) = 180°
6<B- 48 = 180°
add 48 to both sides
6<B-48+48 = 180+48
6<B = 228
<B = 228/6
<B =38°
To get the other angles of the triangle;
Since <A = 2<B from equation 2;
<A = 2(38)
<A = 76°
Also <C = 3<B-48 from equation 3;
<C = 3(38)-48
<C = 114-48
<C = 66°
<em>Hence the measures of the angles of the triangle are 38°, 66° and 76°</em>
Answer:
school building, so the fourth side does not need Fencing. As shown below, one of the sides has length J.‘ (in meters}. Side along school building E (a) Find a function that gives the area A (I) of the playground {in square meters) in
terms or'x. 2 24(15): 320; - 2.x (b) What side length I gives the maximum area that the playground can have? Side length x : [1] meters (c) What is the maximum area that the playground can have? Maximum area: I: square meters
Step-by-step explanation:
