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forsale [732]
3 years ago
5

HELP! SHOW ALL WORK AND EXPLAIN. :P

Mathematics
2 answers:
weeeeeb [17]3 years ago
7 0
♥It says that he adds 12$ each week, and by the end of 3 weeks he had 60. Well if you do 12*3
And that =36.
But as you can see its not 60 so we have to find out how much money he had in there before.
He had 24$ in there before he started doing this.
You can find this by doing 36+x=60 and 36+24=60.
Now if you do 12*15
You get 180.
Now add the 24 dollars he already had in there.
180+24=204
He had 204$ at the end of wk.15
♥Hope this helps!♥
Musya8 [376]3 years ago
4 0
12x3=36 This means that Gary already has money in the bank. So if u do 60-36 you get 24. If u then do 12x15 you get 180 Then u need to add the 24 on 180+24= 204 The answer is to £204
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What is 9 5/6 - 2 1/3
Mariana [72]
9 5/6 - 2 1/3 is 7 1/2.

You could get this answer by finding the same denominator of the fractions. The LCM of both is 6. Multiply the 1 of the second fraction 2 times because you had to multiply the denominator 2 times to get to 6. 
You should have 2 2/6.

Now get 9 5/6 - 2 2/6.

The answer is 7 3/6, simplifies into 7 1/2.
9 5/6 - 2 1/3 is 7 1/2.


5 0
3 years ago
Read 2 more answers
I need to double check a answer. For measure 1 and 3 I got 117, is that right? But for measure 2 I got 63 which is wrong but I h
cupoosta [38]

Answer:

All are 63

Step-by-step explanation:

m∠1 = 180 - 117 = 63 (linear pair)

m∠2 = 63 (alternate interior angle with ∠1)

m∠3 = m∠1 = 63 (isosceles triangle property)

Hope it helps :)

Please mark my answer as the brainliest

3 0
3 years ago
In a random sample of 8 ​people, the mean commute time to work was 35.5 minutes and the standard deviation was 7.4 minutes. A 90
konstantin123 [22]

Answer:

Margin of Error = 5.4088 ;

Confidence interval = (30.1 ; 40.9)

Interval estimate are almost the same

Step-by-step explanation:

Given that :

Population standard deviation, σ = 9.3

Sample size, n = 8

Xbar = 35.5

Confidence level = 90%

The confidence interval:

Xbar ± Margin of error

Margin of Error = Zcritical * σ/sqrt(n)

Zcritical at 90% = 1.645

Margin of Error = 1.645 * 9.3/sqrt(8) = 5.4088

Confidence interval :

Xbar ± Margin of error

35.5 ± 5.4088

Lower boundary = (35.5 - 5.4088) = 30.0912 = 30.1

Upper boundary = (35.5 + 5.4088) = 40.9088 = 40.9

(30.1 ; 40.9)

T distribution =. (30.5 ; 40.5)

Normal distribution = (30.1, 40.9)

4 0
3 years ago
Dang it these are tricky for me can somebody help?
erica [24]

Answer:

It has no perfect square factors, unless you count 1 = 1^2. That's sort of a degenerate case we don't usually count, since every integer has that factor. We would usually say that 1290 is a square-free integer. Hope this helps!!

5 0
3 years ago
Samuel is going to a carnival that has games and rides. Each game costs $2 and each ride costs $5. Samuel spent $60 altogether o
Stells [14]
Think of it as a problem with only the equations so we know the exact numbers of each ride and each cost now we need to do some division and multiplication
2 games and 4 rides
6 0
3 years ago
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