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2 years ago

Y varies directly as the square of x. If y is 25 when x is 3, find y when x is 2

Mathematics

1 answer:

netineya [11]2 years ago

8 0

Answer:

16.6666666667

Step-by-step explanation:

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padilas [110]

Answer:

largest: R
smallest: K

Step-by-step explanation:

The slope of the graph at x=0 is related to the value of b. It is also proportional to the value of a, which is the same for all but curve B. The red curve R has the largest slope at x=0, (much larger than 3/4 the slope of curve B), so curve R has the greatest value of b.

Similarly, the smallest value of b will correspond to the curve with the smallest (most negative) slope. That would be curve K. Curve K has the smallest value of b.

7 0

2 years ago

Please help asap, answer the following questions about the centroid of the triangle:

Naya [18.7K]

Answer:

CE = 15

CD = 10

Step-by-step explanation:

DE is 1/3 of the total line

DE = 5

CE is 3/3 of the line 5 × 3 = 15 which is your whole line

CD is 2/3 of the line so you would need to 5 × 2 = 10

6 0

2 years ago

What should be the first step in adding these equations to eliminate y? 12x-2y=-1

weqwewe [10]

Ensure that y in both sets have a similar co-efficient

3 0

3 years ago

Suppose cos(x)= -1/3, where π/2 ≤ x ≤ π. What is the value of tan(2x). EDGE

AVprozaik [17]

Answer:

Step-by-step explanation:

We are given that:

$\displaystyle \cos x = -\frac{1}{3}\text{ where } \pi /2 \leq x \leq \pi$

And we want to find the value of tan(2x).

Note that since x is between π/2 and π, it is in QII.

In QII, cosine and tangent are negative and only sine is positive.

We can rewrite our expression as:

$\displaystyle \tan(2x)=\frac{\sin(2x)}{\cos(2x)}$

Using double angle identities:

$\displaystyle \tan(2x)=\frac{2\sin x\cos x}{\cos^2 x-\sin^2 x}$

Since cosine relates the ratio of the adjacent side to the hypotenuse and we are given that cos(x) = -1/3, this means that our adjacent side is one and our hypotenuse is three (we can ignore the negative). Using this information, find the opposite side:

$\displaystyle o=\sqrt{3^2-1^2}=\sqrt{8}=2\sqrt{2}$

So, our adjacent side is 1, our opposite side is 2√2, and our hypotenuse is 3.

From the above information, substitute in appropriate values. And since x is in QII, cosine and tangent will be negative while sine will be positive. Hence: