Step-by-step explanation:
A pentagonal prism is a prism having two pentagonal bases and five rectangular sides. It is a heptahedron.
The regular right pentagonal prism is uniform polyhedron . Its dual polyhedron is the pentagonal dipyramid.
The surface area and volume for the right regular pentagonal prism of unit edge length are
S = 5+1/2sqrt(5(5+2sqrt(5)))
(1)
V = 1/4sqrt(5(5+2sqrt(5))).
The linear equation is “y = 1/4 + 40”.
The answer is 400 because 40.00*8.5 is 340.00. Add on the 60 dollar service charge and get 400.00.
Hope this helped :)
Answer:
So the greatest common factor is 3 for sure
Step-by-step explanation:
54x^4y^5z^2
i could be wrong but i am sure that's it
Step One
======
Find the length of FO (see below)
All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)
Step Two
======
Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ
Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.
FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)] \
OJ = ??
[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2 Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2 Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2 Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )
Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.
