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Mazyrski [523]
2 years ago
10

Find three consctive postive integers such that the prodect of the median integer and the largest integer is 72

Mathematics
1 answer:
Tcecarenko [31]2 years ago
8 0

Answer: 7,8,9

Step-by-step explanation:

Let the numbers be a, a+1 and a+2. Therefore, based on the question, this will be:

= (a + 1)(a + 2) = 72

a² + 2a + a + 2 = 72

a² + 3a + 2 - 72 = a

a² + 3a - 70 = 0

a² + 10a - 7a - 70 = 0

a(a + 10) - 7(a + 10)

a - 7 = 0

a = 7

Since a = 7

a + 1 = 7+1 = 8

a + 2 = 7+2 = 9

The numbers are 7,8 and 9

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3 0
3 years ago
Coffee company wants to make sure that their coffee is being served at the right temperature. If it is too hot, the customers co
andrey2020 [161]

Answer:

The average temperature of coffee in the sample, which is 70.2.

Step-by-step explanation:

The population is all the costumers. The company has determined that they want the average coffee temperature to be 65 degrees C. So, 65 degrees C is the average of the population.

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3 0
3 years ago
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5 0
2 years ago
A TRAIN TRAVELING AT A CONSTANT RATE OF SPEED COVERS 360 KILOMETERS IN 6 HOURS WHAT IS THE SPEED OF THE TRAIN
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5 0
3 years ago
Read 2 more answers
What is the minimum number of bits required to store each binary string of length 50? (b) what is the minimum number of bits req
antiseptic1488 [7]
In order to answer the above question, you should know the general rule to solve these questions.
The general rule states that there are 2ⁿ subsets of a set with n number of elements and we can use the logarithmic function to get the required number of bits.
That is: 
log₂(2ⁿ) = n number of <span>bits
</span>
a). <span>What is the minimum number of bits required to store each binary string of length 50?
</span>
Answer: In this situation, we have n = 50. Therefore,  2⁵⁰ binary strings of length 50 are there and so it would require:

                                                     log₂(2⁵⁰) <span>= 50 bits.

b). </span><span>what is the minimum number of bits required to store each number with 9 base of ten digits?
</span>
Answer: In this situation, we have n = 50. Therefore, 10⁹ numbers with 9 base ten digits are there and so it would require:

                                                     log2(109)= 29.89 
<span>                                                                     = 30 bits. (rounded to the nearest                                                                                                                        whole #)

c).  </span><span>what is the minimum number of bits required to store each length 10 fixed-density binary string with 4 ones?
</span>
Answer: There is (10,4) length 10 fixed density binary strings with 4 ones and
so it would require:
                                                     log₂(10,4)=log₂(210) = 7.7
                                                                    = 8 bits. (rounded to the nearest                                                                                                                        whole #)
4 0
3 years ago
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