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tensa zangetsu [6.8K]
4 years ago
14

Simplify number 17 please

Mathematics
2 answers:
SpyIntel [72]4 years ago
5 0
( \frac{4x^{5}y}{16xy^{4}} )^{3}\\
(\frac{1x^{4}}{4y^{3}})^{3}\\
\frac{x^{4*3}}{4^{3}y^{3*3}}\\\\
\frac{x^{12}}{64y^{9}}
Brrunno [24]4 years ago
4 0
64x^15y^3/4096x^3y^12
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Answer:

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Step-by-step explanation:

There is a common difference d between consecutive terms, that is

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A recursive rule allows a term to be found by adding d to the previous term, thus

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vampirchik [111]

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3 years ago
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7 0
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