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tensa zangetsu [6.8K]
4 years ago
14

Simplify number 17 please

Mathematics
2 answers:
SpyIntel [72]4 years ago
5 0
( \frac{4x^{5}y}{16xy^{4}} )^{3}\\
(\frac{1x^{4}}{4y^{3}})^{3}\\
\frac{x^{4*3}}{4^{3}y^{3*3}}\\\\
\frac{x^{12}}{64y^{9}}
Brrunno [24]4 years ago
4 0
64x^15y^3/4096x^3y^12
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Please explain your answer as well. THX!!
telo118 [61]

Answer:

The correct option is the first one.

Step-by-step explanation:

We know that 14 men and 24 women applied for a job. So a total of 38 persons applied for that job.

But there are 4 ways a man can be chosen. It can be the first person chosen, the second, the third of the fourth one.

So we know that the number of ways that four people can be selected out of 38 people is  38C4=73,815.

Also the number of ways 3 woman can be selected is 14*24C3 =14*2024 = 28,336.

Then, the probability of randomly selecting a group with 3 women is 28,336/73,815=0.3838

The correct option is the first one.

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I'm gonna hazard a guess at 309.
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