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Zigmanuir [339]
3 years ago
5

Convert to a fraction in simplest terms: .45

Mathematics
2 answers:
photoshop1234 [79]3 years ago
4 0

Answer:

9/20

Step-by-step explanation:

aliya0001 [1]3 years ago
4 0
9/20 is the answwrrrr
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Phoenix is selling cookies for $2 each and cups of lemonade for $1.50 each. She hopes to raise $50. On scratch paper, write an e
Nadusha1986 [10]
You can divide 50 by 5 (2+(1.50x2)) 50/5 is 10 10x + 20y.

Happy studying ^-^



8 0
3 years ago
2 point) what is the height of a d-heap that contains n elements? the height should be a function of n and
belka [17]
Assuming a d-heap means the order of the tree representing the heap is d.
Most of the computer applications use binary trees, so they are 2-heaps.

A heap is a complete tree where each level is filled (complete) except the last one (leaves) which may or may not be filled.

The height of the heap is the number of levels.  Hence the height of a binary tree is Ceiling(log_2(n)), for example, for 48 elements, log_2(48)=5.58.
Ceiling(5.58)=6.  Thus a binary tree of 6 levels contains from 2^5+1=33 to 2^6=64 elements, and 48 is one of the possibilities.  So the height of a binary-heap with 48 elements is 6.

Similarly, for a d-heap, the height is ceiling(log_d(n)).



6 0
3 years ago
The segments shown below could form a triangle ac=9. cb=8. ba=17
krek1111 [17]
The lengths of sides of a triangle have to satisfy the triangle inequality, which states that the sum of the two shorter sides must exceed the length of the third side.

Here 9+8=17 (not greater), so these segments do not form a triangle.
8 0
3 years ago
Read 2 more answers
Prove that $5^{3^n} + 1$ is divisible by $3^{n + 1}$ for all nonnegative integers $n.$
Viktor [21]

When n=0, we have

5^{3^0} + 1 = 5^1 + 1 = 6

3^{0 + 1} = 3^1 = 3

and of course 3 | 6. ("3 divides 6", in case the notation is unfamiliar.)

Suppose this is true for n=k, that

3^{k + 1} \mid 5^{3^k} + 1

Now for n=k+1, we have

5^{3^{k+1}} + 1 = 5^{3^k \times 3} + 1 \\\\ ~~~~~~~~~~~~~ = \left(5^{3^k}\right)^3 + 1^3 \\\\ ~~~~~~~~~~~~~ = \left(5^{3^k} + 1\right) \left(\left(5^{3^k}\right)^2 - 5^{3^k} + 1\right)

so we know the left side is at least divisible by 3^{k+1} by our assumption.

It remains to show that

3 \mid \left(5^{3^k}\right)^2 - 5^{3^k} + 1

which is easily done with Fermat's little theorem. It says

a^p \equiv a \pmod p

where p is prime and a is any integer. Then for any positive integer x,

5^3 \equiv 5 \pmod 3 \implies (5^3)^x \equiv 5^x \pmod 3

Furthermore,

5^{3^k} \equiv 5^{3\times3^{k-1}} \equiv \left(5^{3^{k-1}}\right)^3 \equiv 5^{3^{k-1}} \pmod 3

which goes all the way down to

5^{3^k} \equiv 5 \pmod 3

So, we find that

\left(5^{3^k}\right)^2 - 5^{3^k} + 1 \equiv 5^2 - 5 + 1 \equiv 21 \equiv 0 \pmod3

QED

5 0
2 years ago
Simplify the expression
raketka [301]

Answer:

147

Step-by-step explanation:

82+9(12÷3×2)-7

82+9(4×2)-7

82+9(8)-7

82+72-7

154-7

147

Follow PEMDAS

3 0
3 years ago
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