Answer:
Explanation:
mass of the solution m = 1.6 + 75 = 76.6 g
fall in temperature = 25 - 23.34 = 1.66°C
heat absorbed = mass x specific heat x fall in temperature
= 76.6 x 1.66 x 4.18
= 531.5 J .
= .5315 kJ .
mol weight of ammonium nitrate = 80 g
heat absorbed by 1.6 g = .5315 kJ
heat absorbed by 80 g or one mole = 26.575 kJ
enthalpy change ΔH = +26.575 kJ
b )
enthalpy of hydration = 2630 kJ / mol
lattice energy = enthalpy of hydration + enthalpy change
= 2630 + 26.575
= 2656.575 kJ .
Answer:
12.78
Explanation:
pOH= -log(0.0600) = 1.22184875
pH= 14-1.22184875 = 12.78
The number of mole of NaOH that was used, given that 3.85 mL of 10.0 M NaOH is used in the reaction is 0.0385 mole
<h3>How do I determine the number of mole of NaOH?</h3>
We know that molarity is related to number of mole and volume according to the following formula:
Molarity = number of mole / Volume
With the above formula, we can determine the number of mole of NaOH. Details below
The following data were obtained from the question:
- Volume = 3.85 mL = 3.85 / 1000 = 0.00385 L
- Molarity = 10.0 M
- Number of mole of NaOH =?
Molarity = number of mole / Volume
Cross multiply
Number of mole = molarity × volume
Number of mole of NaOH = 10 × 0.00385
Number of mole of NaOH = 0.0385 mole
Thus, the number of mole of NaOH is 0.0385 mole
Learn more about number of mole:
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