There are several ways to give an object potential energy. One can move the object against the force of gravity to increase. One can also stretch an object out or put pressure on it.
Answer : The partial pressure of the 
in the tank in psia is, 32.6 psia.
Explanation :
As we are given 75 % and 25 % 
in terms of volume.
First we have to calculate the moles of and .
Now we have to calculate the mole fraction of .
Now we have to calculate the partial pressure of the gas.
conversion used : (1 Kpa = 0.145 psia)
Therefore, the partial pressure of the in the tank in psia is, 32.6 psia.
Note that this is occurring at STP, where 22.4L of any gas is equal to 1mol of that gas.
First, convert the liters of O₂ to moles of O₂ using the conversion factor 22.4LO₂ = 1molO₂.
8.6LO₂ × 1molO₂/22.4LO₂
= 8.6/22.4
≈ 0.3839molO₂
Next, convert moles of O₂ to moles of H₂O. In the balanced equation, the coefficients show that there are 2 moles of H₂O for every mole of O₂. So, use the conversion factor 1molO₂ = 2molH₂O.
0.3839molO₂ × 2molH₂O/1molO₂
= 0.3839 × 2
= 0.7678molH₂O
Finally, convert the moles of H₂O to liters of H₂O using the same conversion factor from before, 22.4LH₂O = 1molH₂O.
0.7678molH₂O × 22.4LH₂O/1molH₂O
= 0.7678 × 22.4
≈ 17LH₂O
So, the answer is 17 liters of gaseous water is collected! Note that its rounded to 17 because the measurement given in the problem has 2 sig figs. Hope that helps! :)
I believe the answer is C.
The answer is 2 more oxygen is needed
