All categories

3 years ago

Simplify the screenshot below

Mathematics

1 answer:

djyliett [7]3 years ago

6 0

Answer:

-4x - 16y

Step-by-step explanation:

Given:

-4(3x - 2x + 4y)

Required:

Simplify

Solution:

To simplify, apply the distributive property by multiplying every term that is inside the brackets by -4

Thus:

-4*3x -4*-2x -4*+4y

-12x + 8x - 16y

Add like terms

-4x - 16y

You might be interested in

Add and simplify<br><br> (3x2+7)+(x2−6x+4)

juin [17]

4 $x^{2}$ -6x+11

5 0

3 years ago

Mrs. Terrace cut a small birthday cake into 6 equal pieces for 6 children. One child was not hungry, so she gave the birthday bo

ELEN [110]

Missing part of question:

Draw a tape diagram to show how much cake each of the five children received.

Answer:

See attachment

Step-by-step explanation:

Given

$Equal\ Pieces = 6$

$Children = 5$

Required

Tape diagram to represent the scenario

Because one child is not hungry, the number of children to share the cake becomes 6.

So, first we calculate the share of each child.

$Share = \frac{Pieces}{Children}$

$Share = \frac{6}{5}$

$Share = 1.2$

See attachment for tape diagram

The tape diagram implies that:

$5 * 1.2 = 6$

$\frac{6}{1.2} = 5$

$\frac{6}{5} = 1.2$

4 0

3 years ago

The box plots show the weights, in pounds, of the dogs in two different animal shelters. Weights of Dogs in Shelter A 2 box plot

katovenus [111]

Answer:

1) The median weight for shelter A is greater than that for shelter B.

True, the median weight for shelter A is 21 pounds as compared to the 18 pounds median weight for shelter B.

4) The data for shelter B are a symmetric data set.

True, the median is exactly 2 pounds away from each quartile which means it is symmetric.

5) The interquartile range of shelter A is greater than the interquartile range of shelter B.

True, the interquartile range of shelter A is 11 pounds as compared to the 4 pounds interquartile range of shelter B.

Step-by-step explanation:

We are given two box-plots, a box plot basically shows 5 statistical characteristics of a data set and they are

1. minimum value

2. Lower quartile

3. Median value

4. Upper quartile

5. Maximum value

Box-plot of dogs in shelter A:

The whiskers range from 8 to 30

Which means that the range is = 30 - 8 = 22

The box ranges from 17 to 28

Which means that the interquartile range is = 28 - 17 = 11

21 - 17 = 4

28 - 21 = 9

The median is not equal distance away from each quartile which means that the box-plot is not symmetric.

A line divides the box at 21

Which means that the median is = 21

Box-plot of dogs in shelter B:

The whiskers range from 10 to 28

Which means that the range is = 28 - 10 = 20

The box ranges from 16 to 20

Which means that the interquartile range is = 20 - 16 = 4

18 - 16 = 2

20 - 18 = 2

The median is exactly 2 pounds away from each quartile which means it is symmetric.

A line divides the box at 18

Which means that the median is = 18

Which is true of the data in the box plots?

1) The median weight for shelter A is greater than that for shelter B.

True, the median weight for shelter A is 21 pounds as compared to the 18 pounds median weight for shelter B.

2) The median weight for shelter B is greater than that for shelter A.

False

3) The data for shelter A are a symmetric data set.

False

4) The data for shelter B are a symmetric data set.

True

5) The interquartile range of shelter A is greater than the interquartile range of shelter B.

True, the interquartile range of shelter A is 11 pounds as compared to the 4 pounds interquartile range of shelter B.

5 0

4 years ago

0.08 is 10 time as great as?

olga_2 [115]

It is 10 times as great as 0.008.

4 0

3 years ago

HELP PLEASE!! HURRY!

otez555 [7]

The second choice is correct you are given that the rate of A is > B.
Slope formula = $\frac{y2-y1}{x2-x1}$

The rate of A is $\frac{6-3}{4-2}=
 \frac{3}{2}$
Thefore B is < $\frac{3}{2}$ or 1.5

Choice 1) I choose the first 2 points from table
$(3,6.3),(4,8.4)= \frac{8.4-6.3}{4-3}= \frac{2.1}{1}$ which is greater than A and not the correct answer

Choice 2) I choose the first 2 points from table
$(3,2.25),(6,4.5)= \frac{4.5-2.25}{6-3} = \frac{2.25}{3}= 0.75$
which is less than A and the correct answer

Choice 3) I choose the first 2 points from table
$(3,5.4),(4,7.2)= \frac{7.2-5.4}{4-3} = \frac{1.8}{1}$ which is greater than A and not the correct answer

3 0

3 years ago